we are looking for
5-2
5-4
5-6 or 3 cases
prob of your event = 3/36 = 1/12
5-2
5-4
5-6 or 3 cases
prob of your event = 3/36 = 1/12
Step 1: Determine the number of favorable outcomes:
The red die has six possible outcomes (numbers 1-6) and we want it to show a 5, so there is only 1 favorable outcome for the red die.
The blue die also has six possible outcomes (numbers 1-6), but we want it to show an even number, which includes 2, 4, and 6. So there are 3 favorable outcomes for the blue die.
Step 2: Determine the total number of possible outcomes:
Since each die has six possible outcomes, the total number of possible outcomes for both dice is 6 x 6 = 36.
Step 3: Calculate the probability:
The probability is given by the number of favorable outcomes divided by the total number of possible outcomes.
So, the probability is 1 (favorable outcomes for the red die) x 3 (favorable outcomes for the blue die) / 36 (total possible outcomes) = 3/36 = 1/12.
Therefore, the probability that the red die shows a 5 and the blue die shows an even number is 1/12.
Total number of outcomes: When two dice are tossed, each die has 6 possible outcomes (numbers 1 to 6). Since we are considering both dice, the total number of outcomes is 6 * 6 = 36.
Favorable outcomes: We want the red die to show a 5, which is only 1 possible outcome. Additionally, we want the blue die to show an even number, which can be 2, 4, or 6. Hence, the total number of favorable outcomes is 1 * 3 = 3.
Therefore, the probability that the red die shows a 5 and the blue die shows an even number is given by:
Probability = (Number of favorable outcomes) / (Total number of outcomes) = 3/36 = 1/12.
So, the probability is 1/12.