A 0.2-kilogram softball is thrown toward a catcher’s mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher’s mitt?(1 point)
Responses
40 N
40 N
8.2 N
8.2 N
1.6 N
1.6 N
7.8 N
is 1.6 N the correct answer??
No, 1.6 N is not the correct answer.
To find the force with which the ball will hit the catcher's mitt, we can use the equation F = m*a, where F is the force, m is the mass, and a is the acceleration.
In this case, the mass of the ball is given as 0.2 kg and the acceleration is given as 8 m/s^2.
Therefore, the force with which the ball will hit the catcher's mitt is calculated as follows:
F = 0.2 kg * 8 m/s^2 = 1.6 N
So the correct answer is indeed 1.6 N.
To calculate the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion: F = ma, where F is the force, m is the mass, and a is the acceleration.
In this case, the mass of the softball is 0.2 kilograms, and the acceleration is 8 meters per second squared. Plugging these values into the equation, we get:
F = (0.2 kg)(8 m/s^2)
F = 1.6 N
Therefore, the correct answer is 1.6 N.
To determine the force with which the ball will hit the catcher's mitt, we need to use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a). In this case, the mass of the ball is 0.2 kilograms and the acceleration is 8 meters per second squared.
So, we can calculate the force by multiplying the mass and acceleration:
F = m * a
F = 0.2 kg * 8 m/s^2
F = 1.6 N
Therefore, the correct answer is 1.6 N.