A 0.2-kilogram softball is thrown toward a catcher’s mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher’s mitt?(1 point)
Responses
7.8 N
7.8 N
8.2 N
8.2 N
40 N
40 N
1.6 N
To determine the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion.
The formula for force is:
Force = mass x acceleration
Given that the mass of the softball is 0.2 kilograms and the acceleration is 8 meters per second squared, we can substitute these values into the formula:
Force = 0.2 kg x 8 m/s^2
Force = 1.6 Newtons
Therefore, the ball will hit the catcher's mitt with a force of 1.6 N.
To calculate the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a).
Given:
Mass (m) = 0.2 kg
Acceleration (a) = 8 m/s²
Using the formula:
F = m * a
Plugging in the values:
F = 0.2 kg * 8 m/s²
F = 1.6 N
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 N.
To find the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a). The mass of the softball is given as 0.2 kilograms, and the acceleration is given as 8 meters per second squared.
So, the force can be calculated as:
F = m * a
F = 0.2 kg * 8 m/s²
F = 1.6 Newtons
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 Newtons.