One molecule of bromine (B*r_{2}) and two molecules of potassium chloride (KCI) combine in a reaction. How many atoms are in the products? (1 point)
O six
O two
O four
O three
To determine the number of atoms in the products of the reaction, we need to calculate the total number of atoms present.
1 molecule of bromine (Br2) contains 2 bromine atoms (2 x Br = 2 Br).
2 molecules of potassium chloride (KCl) contain 2 potassium atoms (2 x K = 2 K) and 2 chlorine atoms (2 x Cl = 2 Cl).
Therefore, the total number of atoms in the products is 2 bromine atoms + 2 potassium atoms + 2 chlorine atoms = 6 atoms.
So the correct answer is "O six."
To determine the number of atoms in the products, we need to calculate the total number of atoms in each molecule and then add them together.
Starting with the reactants, bromine (Br2) is a diatomic molecule, meaning it consists of two bromine atoms bonded together. Therefore, one molecule of bromine contains two bromine atoms.
Potassium chloride (KCl) is a simple compound consisting of one potassium atom (K) and one chlorine atom (Cl) per molecule. Therefore, one molecule of potassium chloride contains one potassium atom and one chlorine atom.
Given that we have one molecule of bromine and two molecules of potassium chloride in the reaction, we can now calculate the total number of atoms in the products.
Bromine will remain as Br2 in the products, so we have 2 bromine atoms.
For potassium chloride, we have one potassium atom from each molecule, so we have 1 potassium atom × 2 molecules = 2 potassium atoms. Similarly, we have one chlorine atom from each molecule, so we have 1 chlorine atom × 2 molecules = 2 chlorine atoms.
Adding them together, we have:
Bromine atoms + Potassium atoms + Chlorine atoms
= 2 bromine atoms + 2 potassium atoms + 2 chlorine atoms
= 6 atoms
Therefore, the total number of atoms in the products is six. So the correct answer is "O six".