A 0.2-kilogram softball is thrown toward a catcher's mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher's mitt?
A. 40 N
B. 7.8 N
C. 8.2 N
D. 1.6 N
The force (F) can be calculated using Newton's second law of motion, which states that force is equal to mass (m) multiplied by acceleration (a): F = m * a.
Given:
m = 0.2 kg
a = 8 m/s²
Using the above values, we can calculate the force:
F = 0.2 kg * 8 m/s²
F = 1.6 N
Therefore, the ball will hit the catcher's mitt with a force of 1.6 Newtons. The correct answer is D. 1.6 N.
To find the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion:
Force = mass x acceleration
Given:
Mass of the ball (m) = 0.2 kg
Acceleration (a) = 8 m/s^2
Using the equation, we can calculate the force:
Force = 0.2 kg x 8 m/s^2
Force = 1.6 N
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 Newtons. Option D, 1.6 N, is the correct answer.
To determine the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a).
In this case, the mass of the softball is given as 0.2 kilograms, and the acceleration is given as 8 meters per second squared. So, the formula becomes:
F = m * a
F = 0.2 kg * 8 m/s^2
F = 1.6 N
Therefore, the ball will hit the catcher's mitt with a force of 1.6 Newtons. Thus, the correct answer is option D: 1.6 N.