Expand 6(x+1).

Expanding the expression 6(x+1), we use the distributive property to distribute the 6 to both terms inside the parentheses:

6(x+1) = 6 * x + 6 * 1

Simplifying further:

= 6x + 6

Expand 4(3z-7)

Expanding the expression 4(3z-7), we use the distributive property to distribute the 4 to both terms inside the parentheses:

4(3z-7) = 4 * 3z + 4 * (-7)

Simplifying further:

= 12z - 28

Expand -5(2q+8)

Expanding the expression -5(2q+8), we use the distributive property to distribute the -5 to both terms inside the parentheses:

-5(2q+8) = -5 * 2q + -5 * 8

Simplifying further:

= -10q - 40

Expand 7/10 (5d+6)

Expanding the expression (7/10)(5d+6), we use the distributive property to distribute the factor 7/10 to both terms inside the parentheses:

(7/10)(5d+6) = (7/10) * 5d + (7/10) * 6

Simplifying further:

= 7/10 * 5d + 7/10 * 6

= (7/10)(5d) + (7/10)(6)

= (7/10) * 5d + (7/10) * 6

= (35/10)d + (42/10)

= 35d/10 + 42/10

= (35d + 42)/10

Thus, the expanded form of 7/10 (5d+6) is (35d + 42)/10.

expand -5/8 (3p+8)

Expanding the expression (-5/8)(3p+8), we use the distributive property to distribute the factor -5/8 to both terms inside the parentheses:

(-5/8)(3p+8) = (-5/8) * 3p + (-5/8) * 8

Simplifying further:

= (-15/8)p + (-40/8)

= -15p/8 - 5

Thus, the expanded form of -5/8 (3p+8) is -15p/8 - 5.

Expand 5(y+2) using the distributive property.