Expand 6(x+1).
Expanding the expression 6(x+1), we use the distributive property to distribute the 6 to both terms inside the parentheses:
6(x+1) = 6 * x + 6 * 1
Simplifying further:
= 6x + 6
Expand 4(3z-7)
Expanding the expression 4(3z-7), we use the distributive property to distribute the 4 to both terms inside the parentheses:
4(3z-7) = 4 * 3z + 4 * (-7)
Simplifying further:
= 12z - 28
Expand -5(2q+8)
Expanding the expression -5(2q+8), we use the distributive property to distribute the -5 to both terms inside the parentheses:
-5(2q+8) = -5 * 2q + -5 * 8
Simplifying further:
= -10q - 40
Expand 7/10 (5d+6)
Expanding the expression (7/10)(5d+6), we use the distributive property to distribute the factor 7/10 to both terms inside the parentheses:
(7/10)(5d+6) = (7/10) * 5d + (7/10) * 6
Simplifying further:
= 7/10 * 5d + 7/10 * 6
= (7/10)(5d) + (7/10)(6)
= (7/10) * 5d + (7/10) * 6
= (35/10)d + (42/10)
= 35d/10 + 42/10
= (35d + 42)/10
Thus, the expanded form of 7/10 (5d+6) is (35d + 42)/10.
expand -5/8 (3p+8)
Expanding the expression (-5/8)(3p+8), we use the distributive property to distribute the factor -5/8 to both terms inside the parentheses:
(-5/8)(3p+8) = (-5/8) * 3p + (-5/8) * 8
Simplifying further:
= (-15/8)p + (-40/8)
= -15p/8 - 5
Thus, the expanded form of -5/8 (3p+8) is -15p/8 - 5.
Expand 5(y+2) using the distributive property.
Expanding the expression 5(y+2) using the distributive property, we distribute the 5 to both terms inside the parentheses:
5(y+2) = 5 * y + 5 * 2
Simplifying further:
= 5y + 10
Therefore, the expanded form of 5(y+2) is 5y + 10.
Expand -5(-3 - 11g)
Expanding the expression -5(-3 - 11g), we use the distributive property to distribute the -5 to both terms inside the parentheses:
-5(-3 - 11g) = -5 * (-3) - 5 * (-11g)
Simplifying further:
= 15 + 55g
Thus, the expanded form of -5(-3 - 11g) is 15 + 55g.
Expand 1/3(q-6) using the distributive property
Expanding the expression (1/3)(q-6) using the distributive property, we distribute the factor 1/3 to both terms inside the parentheses:
(1/3)(q-6) = (1/3) * q + (1/3) * (-6)
Simplifying further:
= q/3 - 6/3
= q/3 - 2
Therefore, the expanded form of (1/3)(q-6) is q/3 - 2.
Expand 2/5 (-5c+10)
Expanding the expression (2/5)(-5c+10) using the distributive property, we distribute the factor 2/5 to both terms inside the parentheses:
(2/5)(-5c+10) = (2/5) * (-5c) + (2/5) * 10
Simplifying further:
= -10c/5 + 20/5
= -2c + 4
Therefore, the expanded form of (2/5)(-5c+10) is -2c + 4.
Expand -7/6(3g+2)
Expanding the expression (-7/6)(3g+2) using the distributive property, we distribute the factor -7/6 to both terms inside the parentheses:
(-7/6)(3g+2) = (-7/6) * 3g + (-7/6) * 2
Simplifying further:
= -21g/6 - 14/6
= -7g/2 - 7/3
Therefore, the expanded form of (-7/6)(3g+2) is -7g/2 - 7/3.