CaCOs - CO, + CaO
A scientist heats 30 grams of calcium carbonate (CaCO) in the chemical reaction shown. What is the total mass of the products?
To solve this problem, we need to determine the molar mass of each compound involved in the reaction.
The molar mass of CaCO is calculated as follows:
- The molar mass of calcium (Ca) is 40.08 g/mol.
- The molar mass of carbon (C) is 12.01 g/mol.
- The molar mass of oxygen (O) is 16.00 g/mol (there are two oxygen atoms).
Therefore, the molar mass of CaCO is:
40.08 g/mol (Ca) + 12.01 g/mol (C) + (16.00 g/mol (O) * 2) = 100.09 g/mol
Since the scientist has 30 grams of CaCO, we need to determine the number of moles involved in the reaction:
30 g / 100.09 g/mol = 0.2998 mol
From the reaction, we can see that 1 mole of CaCO reacts to produce 1 mole of CO and 1 mole of CaO.
Therefore, we will also obtain 0.2998 mol of CO and 0.2998 mol of CaO.
Finally, to determine the mass of the products, we need to multiply the number of moles by their respective molar mass.
The molar mass of CO is 28.01 g/mol. Therefore, the mass of CO is:
0.2998 mol * 28.01 g/mol = 8.4 grams
The molar mass of CaO is 56.08 g/mol. Therefore, the mass of CaO is:
0.2998 mol * 56.08 g/mol = 16.8 grams
The total mass of the products is the sum of the masses of CO and CaO:
8.4 grams + 16.8 grams = 25.2 grams.
Therefore, the total mass of the products is 25.2 grams.
To determine the total mass of the products in the given chemical reaction, we need to balance the equation properly. It seems that there may be a typo in the equation you provided. The correct balanced equation for the reaction between calcium carbonate (CaCO3) and heat is:
CaCO3 → CaO + CO2
Now we know that 1 mole of CaCO3 has a molar mass of approximately 100.09 g/mol. Since the given reaction involves 30 grams of CaCO3, we need to convert this mass into moles.
Moles of CaCO3 = Mass of CaCO3 / Molar mass of CaCO3
Moles of CaCO3 = 30 g / 100.09 g/mol
Moles of CaCO3 ≈ 0.2999 moles (rounded to four decimal places)
From the balanced equation, we can see that the molar ratio between CaCO3 and CaO is 1:1. This means that the number of moles of CaO produced will be the same as the moles of CaCO3 used.
Therefore, the moles of CaO = 0.2999 moles
The molar mass of CaO is approximately 56.08 g/mol, so we can calculate the mass of CaO using the moles.
Mass of CaO = Moles of CaO × Molar mass of CaO
Mass of CaO = 0.2999 moles × 56.08 g/mol
Mass of CaO ≈ 16.84 grams (rounded to two decimal places)
Hence, the total mass of the products (CaO and CO2) is approximately 16.84 grams.