A scientist heats 30 grams of calcium carbonate (CaCO3) in the chemical reaction shown. What is the total mass of the products?
(1 point)
1.)CaCO3→CO2+CaO
A scientist heats 30 grams of calcium carbonate (CaCO3) in the chemical reaction shown. What is the total mass of the products?(1 point)
A.)10 grams
B.)15 grams
C.)60 grams
D.)30 grams<<<<
2.)Fe+O2→Fe2O3
What happens to atoms of Fe and O2 during the reaction?(1 point)
A.)They are lost.
B.)They are rearranged.<<<<
C.)They maintain their properties.
D.)They gain mass.
3.)What is most likely to occur during a chemical reaction?(1 point)
A.)New atoms are created.
B.)Mass is conserved.<<<<
C.)The original substance maintains its properties.
D.)Molecules of the original substance are lost.
{4.}NaHCO3+HC2H3O2→NaC2H3O2+H2O+CO2
A student mixes baking soda (NaHCO3) and acetic acid (HC2H3O2) to produce a chemical reaction shown. Which statement about the reaction is correct?(1 point)
A.)Atoms of Na are destroyed during the reaction.
B.)Some atoms gain mass after the reaction.
C.)There are more H atoms after the reaction.
D.)The atoms of the reactants are regrouped during the reaction.<<<<
{5.}2H2+O2→2H2O
There are four atoms of hydrogen (H) before the reaction. How many atoms of hydrogen are present after the reaction?
(1 point)
A.)8
B.)2
C.)5
D.)4<<<<
thx the bestanwsers 100 2025
tysm
In order to determine the total mass of the products in the given chemical reaction, we need to understand the stoichiometry and balanced equation of the reaction.
The chemical equation for the reaction of calcium carbonate (CaCO3) when heated is:
CaCO3(s) -> CaO(s) + CO2(g)
From the balanced equation, we can see that one mole of calcium carbonate (CaCO3) will produce one mole of calcium oxide (CaO) and one mole of carbon dioxide (CO2).
Now, let's convert the given mass of calcium carbonate (30 grams) into moles. To do this, we need to know the molar mass of calcium carbonate. The molar mass of CaCO3 is calculated as follows:
(1 atom of Ca x atomic mass of Ca) + (1 atom of C x atomic mass of C) + (3 atoms of O x atomic mass of O)
= (1 x 40.08 g/mol) + (1 x 12.01 g/mol) + (3 x 16.00 g/mol)
= 40.08 g/mol + 12.01 g/mol + 48.00 g/mol
= 100.09 g/mol
Now, using the molar mass of CaCO3, we can calculate the number of moles of CaCO3:
Moles = Mass / Molar mass
Moles = 30 g / 100.09 g/mol
Moles ≈ 0.29988 mol (rounded to five decimal places)
Since the reaction produces equal moles of calcium oxide and carbon dioxide, the number of moles of CaO and CO2 will also be approximately 0.29988 mol each.
Finally, let's calculate the mass of CaO and CO2 by multiplying the respective moles by their molar masses. The molar mass of CaO is 56.08 g/mol, and the molar mass of CO2 is 44.01 g/mol.
Mass of CaO = Moles of CaO x Molar mass of CaO
Mass of CaO = 0.29988 mol x 56.08 g/mol
Mass of CaO ≈ 16.83 g (rounded to two decimal places)
Mass of CO2 = Moles of CO2 x Molar mass of CO2
Mass of CO2 = 0.29988 mol x 44.01 g/mol
Mass of CO2 ≈ 13.20 g (rounded to two decimal places)
Therefore, the total mass of the products (CaO + CO2) is approximately 16.83 grams + 13.20 grams = 30.03 grams (rounded to two decimal places).