The total number of ions in 2,0 g K2SO4
To find the total number of ions in 2.0 g of K2SO4, we need to understand the molecular formula of K2SO4 and the number of ions it dissociates into in water.
The molecular formula of K2SO4 indicates that there are two potassium ions (K+) and one sulfate ion (SO42-) in each formula unit.
The molar mass of K2SO4 is calculated by adding the atomic masses of each element: (2 x Atomic mass of potassium) + Atomic mass of sulfur + (4 x Atomic mass of oxygen)
Atomic mass of potassium (K) = 39.10 g/mol
Atomic mass of sulfur (S) = 32.06 g/mol
Atomic mass of oxygen (O) = 16.00 g/mol
Molar mass of K2SO4 = (2 x 39.10) + 32.06 + (4 x 16.00) = 174.26 g/mol
Using the molar mass, we can calculate the number of moles of K2SO4 in 2.0 g:
Number of moles = mass of substance / molar mass
Number of moles = 2.0 g / 174.26 g/mol ≈ 0.01146 mol
Since each formula unit of K2SO4 yields three ions (2 K+ ions and 1 SO42- ion), we need to multiply the number of moles by the number of ions per formula unit:
Total number of ions = Number of moles x Number of ions per formula unit
Total number of ions = 0.01146 mol x 3 = 0.03438 moles ≈ 2.07 x 10^22 ions
Therefore, the total number of ions in 2.0 g of K2SO4 is approximately 2.07 x 10^22 ions.
To determine the total number of ions in 2.0 g of K2SO4 (potassium sulfate), we need to consider the molar mass and the stoichiometry of the compound.
Step 1: Calculate the molar mass of K2SO4
The molar mass of potassium (K) is approximately 39.10 g/mol.
The molar mass of sulfur (S) is approximately 32.07 g/mol.
The molar mass of oxygen (O) is approximately 16.00 g/mol.
Since K2SO4 has 2 potassium ions (K), 1 sulfur ion (S), and 4 oxygen ions (O), we can calculate the molar mass as follows:
Molar mass of K2SO4 = (2 * molar mass of K) + molar mass of S + (4 * molar mass of O)
= (2 * 39.10 g/mol) + 32.07 g/mol + (4 * 16.00 g/mol)
= 78.20 g/mol + 32.07 g/mol + 64.00 g/mol
= 174.27 g/mol
Step 2: Determine the number of moles of K2SO4
Number of moles = mass / molar mass
= 2.0 g / 174.27 g/mol
≈ 0.01146 mol (rounded to 5 decimal places)
Step 3: Calculate the total number of ions
Since each formula unit of K2SO4 produces 3 ions (2 K+ ions and 1 SO4^2- ion), we can multiply the number of moles by the Avogadro's number to find the total number of ions.
Total number of ions = number of moles * Avogadro's number
= 0.01146 mol * 6.022 x 10^23 ions/mol
≈ 6.908 x 10^21 ions
Therefore, the total number of ions in 2.0 g of K2SO4 is approximately 6.908 x 10^21 ions.