The container that holds the water for the football team is 1/2 full. After pouring in 9 gallons of water, it is 5/6 full. How many gallons can the container hold?
Let X be the capacity of the container.
The container is 1/2 full, so it contains 1/2*X gallons of water.
After pouring 9 gallons of water, it is 5/6 full, so it contains (1/2*X) + 9 = (5/6)*X gallons of water.
Subtracting 1/2*X from both sides, we get 9 = (5/6)*X - (1/2)*X.
Combining like terms, we get 9 = (5/6 - 1/2)*X.
Multiplying both sides by 6/5, we get (6/5)*9 = X.
Multiplying fractions, we get (6*9)/5 = X.
Simplifying the fraction, we get 54/5 = X.
Thus, the container can hold 54/5 gallons of water. Answer: \boxed{10.8}.
Let's denote the capacity of the container by C (in gallons).
According to the given information, the container is initially 1/2 full, which means it contains (1/2) * C gallons of water.
After pouring in 9 gallons of water, the container is now 5/6 full, which means it contains (5/6) * C gallons of water.
Therefore, the difference in the amount of water poured is (5/6) * C - (1/2) * C = 9 gallons.
Simplifying the equation, we can write:
(5/6) * C - (1/2) * C = 9
Multiplying through by 12 (the least common denominator), we have:
10C - 6C = 108
Simplifying, we get:
4C = 108
Dividing both sides by 4, we find:
C = 108 / 4
C = 27
Hence, the container can hold 27 gallons of water.