water flows from a tap at the rate of 27cm cube per second ,into a rectangular container of length 69cm,breadth 30cm, and height 40cm, if at 6:00pm the container was half full what will be the height of water at 6:04pm
To find the height of water at 6:04 pm, we need to calculate the volume of water that flows into the container from 6:00 pm to 6:04 pm and add it to the initial half-full volume.
The initial volume is given by:
Initial volume = (length) x (breadth) x (half height)
= 69cm x 30cm x (40cm/2)
= 62100cm³
The volume of water that flows into the container from 6:00 pm to 6:04 pm is given by:
Volume of water in 4 seconds = Flow rate x Time = 27cm³/s x 4s = 108cm³
So, the final volume at 6:04 pm is:
Final volume = Initial volume + Volume of water in 4 seconds
= 62100cm³ + 108cm³
= 62208cm³
We need to find the height of the water. Let's assume it is h.
Volume of water = (length) x (breadth) x (height)
62208cm³ = 69cm x 30cm x h
62208cm³ = 2070cm² x h
h = 62208cm³ / 2070cm²
h ≈ 30.06 cm
Therefore, the height of the water at 6:04 pm is approximately 30.06 cm.