Calculate the relative molecular mass of
NaNO3
To calculate the relative molecular mass of NaNO3, we need to find the sum of the atomic masses of its constituent atoms.
The atomic mass of Na (Sodium) is 22.99 g/mol.
The atomic mass of N (Nitrogen) is 14.01 g/mol.
The atomic mass of O (Oxygen) is 16.00 g/mol.
Since there is 1 Na, 1 N, and 3 O atoms in NaNO3, we can calculate the relative molecular mass as follows:
(1 x 22.99) + (1 x 14.01) + (3 x 16.00) = 22.99 + 14.01 + 48.00 = 85.00 g/mol
Therefore, the relative molecular mass of NaNO3 is 85.00 g/mol.
Calculate the relative molecular mass of CuSO4.5H20
To calculate the relative molecular mass of CuSO4·5H2O, we need to find the sum of the atomic masses of all its constituent atoms.
The atomic mass of Cu (Copper) is 63.55 g/mol.
The atomic mass of S (Sulfur) is 32.06 g/mol.
The atomic mass of O (Oxygen) is 16.00 g/mol.
The atomic mass of H (Hydrogen) is 1.01 g/mol.
Since there is 1 Cu, 1 S, 4 O, 10 H, and 2 O atoms in CuSO4·5H2O, we can calculate the relative molecular mass as follows:
(1 x 63.55) + (1 x 32.06) + (4 x 16.00) + (10 x 1.01) + (2 x 16.00) = 63.55 + 32.06 + 64.00 + 10.10 + 32.00 = 201.71 g/mol
Therefore, the relative molecular mass of CuSO4·5H2O is 201.71 g/mol.
Calculate the relative molecular mass of Pb(NO3)2
To calculate the relative molecular mass of Pb(NO3)2, we need to find the sum of the atomic masses of all its constituent atoms.
The atomic mass of Pb (Lead) is 207.2 g/mol.
The atomic mass of N (Nitrogen) is 14.01 g/mol.
The atomic mass of O (Oxygen) is 16.00 g/mol.
Since there is 1 Pb, 2 N, and 6 O atoms in Pb(NO3)2, we can calculate the relative molecular mass as follows:
(1 x 207.2) + (2 x 14.01) + (6 x 16.00) = 207.2 + 28.02 + 96.00 = 331.22 g/mol.
Therefore, the relative molecular mass of Pb(NO3)2 is 331.22 g/mol.
To calculate the relative molecular mass of NaNO3 (sodium nitrate), you need to sum up the atomic masses of all the atoms in the compound.
The atomic masses of the individual atoms in NaNO3 are as follows:
Na (sodium) = 22.99 g/mol
N (nitrogen) = 14.01 g/mol
O (oxygen) = 16.00 g/mol
Now, we can calculate the relative molecular mass of NaNO3 by adding up the atomic masses:
Relative molecular mass of NaNO3 = (1 * Na) + (1 * N) + (3 * O)
= 22.99 + 14.01 + (3 * 16.00)
= 22.99 + 14.01 + 48.00
= 85.00 g/mol
Therefore, the relative molecular mass of NaNO3 is 85.00 g/mol.
To calculate the relative molecular mass of NaNO3, we need to know the atomic masses of its constituent elements: sodium (Na), nitrogen (N), and oxygen (O). We can find these atomic masses from the periodic table.
The atomic mass of sodium (Na) is approximately 22.99 g/mol.
The atomic mass of nitrogen (N) is approximately 14.01 g/mol.
The atomic mass of oxygen (O) is approximately 16.00 g/mol.
Now, let's calculate the relative molecular mass of NaNO3:
Relative molecular mass of NaNO3 = (Atomic mass of Na) + (Atomic mass of N) + (3 x Atomic mass of O)
= (22.99 g/mol) + (14.01 g/mol) + (3 x 16.00 g/mol)
= 22.99 g/mol + 14.01 g/mol + 48.00 g/mol
= 85.00 g/mol
Therefore, the relative molecular mass of NaNO3 is 85.00 g/mol.