1.50 g oxide of M,MO2 reacts with excess hydrochloric acid solution ,HCL to produce 386 cm^3 chlorine gas at STP
MO2 + HCL --> MCL + H2O + CL2
Questions
1) balance the equation
2)Determine relative molecular mass of MO2 and relative atomic mass of M
I think you have made a typo. Could that be
MO2 + HCL --> MCL2 + H2O + CL2
1) To balance the equation, we need an equal number of atoms of each element on both sides.
The balanced equation is:
MO2 + 4HCl → MCl2 + 2H2O + Cl2
2) We can determine the relative molecular mass of MO2 by adding up the relative atomic masses of the elements present in MO2. Since MO2 has one M and two O atoms, we need to find the relative atomic mass of M and multiply it by 1, and the relative atomic mass of O and multiply it by 2.
To determine the relative atomic mass of M, we need more information. If you can provide the element M or its atomic number, I can help you calculate the relative atomic mass of M.
1) To balance the equation, we need to make sure that the number of atoms of each element is the same on both sides of the equation.
MO2 + 4HCl → MCl + 2H2O + Cl2
2) In order to determine the relative molecular mass of MO2 and the relative atomic mass of M, we need to use the information given about the reaction.
From the reaction, we know that 1.50 g of MO2 reacted to produce 386 cm^3 of Cl2 at STP.
To determine the relative molecular mass of MO2, we can use the ideal gas law: PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature.
At STP (Standard Temperature and Pressure):
Pressure (P) = 1 atm
Volume (V) = 386 cm^3 = 0.386 dm^3
Temperature (T) = 273 K
R, the ideal gas constant = 0.0821 L·atm/(mol·K)
n = PV/RT
n = (1 atm)(0.386 dm^3) / (0.0821 L·atm/(mol·K))(273 K)
n = 0.017 moles of Cl2
From the balanced equation, we can see that the molar ratio between MO2 and Cl2 is 1:1. Therefore, the number of moles of MO2 is also 0.017 moles.
Now, we can calculate the relative molecular mass of MO2 by dividing the mass of MO2 by the moles of MO2.
Mass of MO2 = 1.50 g
Relative molecular mass of MO2 = Mass of MO2 / Moles of MO2
Relative molecular mass of MO2 = 1.50 g / 0.017 moles
Relative molecular mass of MO2 ≈ 88.24 g/mol
To determine the relative atomic mass of M, we need to subtract the mass of oxygen (O) from the relative molecular mass of MO2.
Oxygen has a relative atomic mass of approximately 16 g/mol.
Relative atomic mass of M = Relative molecular mass of MO2 - Relative atomic mass of O
Relative atomic mass of M = 88.24 g/mol - 16 g/mol
Relative atomic mass of M ≈ 72.24 g/mol
1) To balance the equation, we need to make sure that the number of each element is the same on both sides of the equation. Let's go through the balancing process step by step:
MO2 + HCL -> MCL + H2O + CL2
First, let's balance the elements other than oxygen and hydrogen:
MO2 + 2HCL -> MCL + H2O + CL2
Now, let's balance the oxygen atoms. On the left side, we have two oxygen atoms from the MO2 molecule, and on the right side, we have one oxygen atom from H2O. To balance the oxygen, we need to add another H2O molecule on the right side:
MO2 + 2HCL -> MCL + 2H2O + CL2
Lastly, let's balance the hydrogen atoms. On the left side, we have four hydrogen atoms from the 2HCL molecules, and on the right side, we have four hydrogen atoms from the 2H2O molecules. The equation is now balanced.
2) To determine the relative molecular mass of MO2, we can use the following steps:
First, find the number of moles of chlorine gas (Cl2) produced. We know that the volume of the chlorine gas is 386 cm^3 at STP. At STP, one mole of any gas occupies a volume of 22.4 liters or 22,400 cm^3. So, we can calculate the number of moles of Cl2 as follows:
Number of moles of Cl2 = volume of Cl2 (in cm^3) / 22,400 cm^3/mole
Number of moles of Cl2 = 386 cm^3 / 22,400 cm^3/mole
Next, we need to relate the moles of Cl2 to the moles of MO2. According to the balanced equation, the stoichiometric ratio between Cl2 and MO2 is 1:1. This means that one mole of Cl2 is produced for every mole of MO2 consumed. Therefore, the number of moles of MO2 is the same as the number of moles of Cl2.
Now, calculate the mass of MO2. Given that the mass of the MO2 used is 1.50 g, we can use the molar mass of MO2 to find the number of moles of MO2:
Number of moles of MO2 = mass of MO2 (in grams) / molar mass of MO2
Finally, calculate the relative molecular mass of MO2 by dividing the mass of MO2 by the number of moles of MO2:
Relative molecular mass of MO2 = mass of MO2 / number of moles of MO2
To determine the relative atomic mass of M, we need additional information. The given equation does not provide any direct information about the molar mass or stoichiometry of M.