CH3COOH+NaOH = ?
CH3COOH + NaOH → CH3COONa + H2O
The balanced equation shows that acetic acid (CH3COOH) reacts with sodium hydroxide (NaOH) to produce sodium acetate (CH3COONa) and water (H2O).
The equation CH3COOH + NaOH represents a neutralization reaction between acetic acid (CH3COOH) and sodium hydroxide (NaOH). In this reaction, the acetic acid donates a hydrogen ion (H+) to the hydroxide ion (OH-) from the sodium hydroxide. As a result, water (H2O) and sodium acetate (CH3COONa) are formed. The balanced chemical equation for this reaction is:
CH3COOH + NaOH -> CH3COONa + H2O
So, when acetic acid reacts with sodium hydroxide, it produces sodium acetate and water as the final products.