How many grams of cacl2 formed when 8 moles of chlorine reacts with calcium metal?
The balanced chemical equation for the reaction between chlorine and calcium is:
Ca + Cl2 → CaCl2
From the equation, we can see that 1 mole of calcium reacts with 1 mole of chlorine to form 1 mole of calcium chloride. Therefore, if 8 moles of chlorine react, we need 8 moles of calcium to react as well.
The molar mass of CaCl2 is 110.98 g/mol (40.08 g/mol for calcium and 2x 35.45 g/mol for chlorine). So, to find the mass of CaCl2 formed, we can use:
mass = moles x molar mass
mass = 8 moles x 110.98 g/mol
mass = 887.84 g
Therefore, 887.84 grams of CaCl2 will be formed when 8 moles of chlorine reacts with calcium metal.
To determine the number of grams of CaCl2 formed when 8 moles of chlorine reacts with calcium metal, we first need to write the balanced chemical equation for the reaction:
2 Cl2 + 2 Ca -> 2 CaCl2
From the balanced equation, we can see that 2 moles of Cl2 react with 2 moles of Ca to form 2 moles of CaCl2.
In this case, we have 8 moles of Cl2. Since the mole ratio is 1:1 between Cl2 and CaCl2, we can conclude that 8 moles of Cl2 will also react to give 8 moles of CaCl2.
Next, we need to calculate the molar mass of CaCl2. Calcium has a molar mass of 40.08 g/mol, while chlorine has a molar mass of 35.45 g/mol. Adding these together, we get:
Molar mass of CaCl2 = (40.08 g/mol) + 2(35.45 g/mol) = 111.98 g/mol
Now, we can calculate the mass of CaCl2 formed:
Mass of CaCl2 = Number of moles x Molar mass
Mass of CaCl2 = 8 moles x 111.98 g/mol = 895.84 g
Therefore, when 8 moles of chlorine reacts with calcium metal, 895.84 grams of CaCl2 are formed.