Calculate the mass of cacl2formed when 5mole of chlorine reacts with calcium metal
Ca + Cl2 ==> CaCl2
Look at the coefficients in the balanced equation.
1 mol Cl2 forms 1 mol CaCl2; therefore,
5 mols Cl2 will form 5 moles CaCl2.
Then moles CaCl2 x molar mass CaCl2 = grams CaCl2.
40g
To calculate the mass of CaCl2 formed when 5 moles of chlorine react with calcium metal, we need to determine the balanced chemical equation for the reaction.
The chemical equation for the reaction between chlorine (Cl2) and calcium metal (Ca) can be represented as follows:
2Cl2 + 2Ca -> 2CaCl2
From the balanced equation, we can see that 2 moles of chlorine react with 2 moles of calcium to produce 2 moles of calcium chloride.
Now, we need to find the molar mass of CaCl2. Calcium (Ca) has a molar mass of 40.08 g/mol, and chlorine (Cl) has a molar mass of 35.45 g/mol.
Molar mass of CaCl2 = (40.08 g/mol) + 2 * (35.45 g/mol) = 110.98 g/mol
Next, we'll calculate the mass of CaCl2 formed.
Mass = moles * molar mass
Mass of CaCl2 = 5 moles * 110.98 g/mol = 554.9 g
Therefore, when 5 moles of chlorine react with calcium metal, the mass of CaCl2 formed is 554.9 grams.
To calculate the mass of CaCl2 formed when 5 moles of chlorine (Cl2) react with calcium metal (Ca), we need to determine the balanced chemical equation for the reaction and use stoichiometry.
The balanced chemical equation for the reaction between chlorine and calcium is:
2 Cl2 + 2 Ca -> 2 CaCl2
From the balanced equation, we can see that every 2 moles of Cl2 react with 2 moles of Ca to produce 2 moles of CaCl2.
Since we have 5 moles of Cl2, we need to determine how many moles of CaCl2 will be formed. We can use the stoichiometry of the balanced equation to do this conversion:
5 moles Cl2 * (2 moles CaCl2 / 2 moles Cl2) = 5 moles CaCl2
Therefore, 5 moles of chlorine (Cl2) will react to form 5 moles of calcium chloride (CaCl2).
Next, we need to determine the molar mass of CaCl2, which is the sum of the atomic masses of calcium (Ca) and two chlorine atoms (Cl). The atomic mass of Ca is 40.08 g/mol, and the atomic mass of Cl is 35.45 g/mol. Therefore, the molar mass of CaCl2 is:
40.08 g/mol (Ca) + 2 * 35.45 g/mol (Cl) = 110.98 g/mol
Finally, we can calculate the mass of CaCl2 formed by multiplying the molar mass by the number of moles:
5 moles CaCl2 * 110.98 g/mol = 554.9 g
Therefore, when 5 moles of chlorine react with calcium metal, it will produce 554.9 grams of calcium chloride.