On his recent free-throw attempts, Lester made 39 shots and missed 3 shots. What is the experimental probability that Lester will miss his next free-throw attempt?
The experimental probability is the number of times an event occurred divided by the total number of trials. In this case, the event is missing a free-throw and the number of times it occurred is 3, while the total number of trials is 42 (39 made plus 3 missed). Therefore, the experimental probability that Lester will miss his next free-throw attempt is:
3/42
Simplifying the fraction by dividing both numerator and denominator by 3, we get:
1/14
So the experimental probability is 1/14 or approximately 0.071.
To find the experimental probability of Lester missing his next free-throw attempt, we need to calculate the ratio of the number of times Lester has missed a shot to the total number of shots attempted.
Lester has made 39 shots and missed 3 shots, so the total number of shots attempted is 39 + 3 = 42.
The number of times Lester has missed a shot is 3.
Therefore, the experimental probability that Lester will miss his next free-throw attempt is 3/42, which simplifies to 1/14.
To find the experimental probability of Lester missing his next free-throw attempt, you need to divide the number of missed shots by the total number of shots attempted.
In this case, Lester made 39 shots and missed 3 shots. Therefore, the total number of shots attempted is 39 + 3 = 42.
To calculate the experimental probability of Lester missing the next free-throw attempt, divide the number of missed shots (3) by the total number of shots attempted (42):
P(missing) = Number of missed shots / Total number of shots attempted
= 3 / 42
Simplifying the fraction, the experimental probability of Lester missing his next free-throw attempt is:
P(missing) = 1 / 14
Therefore, the experimental probability that Lester will miss his next free-throw attempt is 1/14.