The rectangular floor of a classroom is 30 feet in length and 33 feet in width. A scale drawing of the floor has a length of 10 inches. What is the perimeter, in inches, of the floor in the scale drawing?

We can start by finding the scale of the drawing. Since the length of the actual floor is 30 feet and the length in the drawing is 10 inches, we can set up the proportion:

30 feet / 10 inches = x feet / 1 inch

Solving for x, we get:

x = (30 feet / 10 inches) * 1 inch
x = 3 feet/inch

So the scale of the drawing is 3 feet/inch.

To find the perimeter in the drawing, we can add up the lengths in each direction and convert to inches using the scale. Going around the classroom:

-The length is 30 feet = 360 inches in real life, so it is 360/3 = 120 inches in the drawing.
-The width is 33 feet = 396 inches in real life, so it is 396/3 = 132 inches in the drawing.
-Going back along the other side, the length is again 120 inches.
-And finally, the width is 132 inches again.

Adding up all four sides, we get:

120 + 132 + 120 + 132 = 504 inches

So the perimeter of the floor in the scale drawing is 504 inches.

Isn't it 42?

You are correct. I apologize for the mistake. The perimeter of the floor in the scale drawing is actually 42 inches.

To find the length of the floor in the drawing, we can set up the proportion:

30 feet / x inches = 10 inches / 1 inch

Solving for x, we get:

x = (30 feet * 1 inch) / 10 inches
x = 3 feet/inch

So the scale of the drawing is 3 feet/inch.

Then to find the perimeter in the drawing, we can add up the lengths in each direction and convert to inches using the scale:

- The length is 30 feet = 360 inches in real life, so it is 360 / 3 = 120 inches in the drawing.
- The width is 33 feet = 396 inches in real life, so it is 396 / 3 = 132 inches in the drawing.
- Going back along the other side, the length is again 120 inches.
- And finally, the width is 132 inches again.

Adding up all four sides, we get:

120 + 132 + 120 + 132 = 504 inches

However, this is the perimeter in real life, not in the drawing. To get the perimeter in the drawing, we need to divide by the scale factor:

504 inches / 3 feet/inch = 168 feet

So the perimeter in the drawing is 168 inches / 3 feet/inch = 56 inches.

Again, I apologize for the confusion and any inconvenience caused by my previous response.

The rectangular floor of a classroom is 36 feet in length and 22 feet in width. A scale drawing of the floor has a length of 18 inches. What is the perimeter, in inches, of the floor in the scale drawing?

Don't make the same mistake again, please!

I apologize for my previous mistakes. Here's the solution for the problem at hand:

We can start by finding the scale of the drawing. Since the length of the actual floor is 36 feet and the length in the drawing is 18 inches, we can set up the proportion:

36 feet / 18 inches = x feet / 1 inch

Solving for x, we get:

x = (36 feet / 18 inches) * 1 inch
x = 2 feet/inch

So the scale of the drawing is 2 feet/inch.

To find the perimeter in the drawing, we can add up the lengths in each direction and convert to inches using the scale. Going around the classroom:

-The length is 36 feet = 432 inches in real life, so it is 432/2 = 216 inches in the drawing.
-The width is 22 feet = 264 inches in real life, so it is 264/2 = 132 inches in the drawing.
-Going back along the other side, the length is again 216 inches.
-And finally, the width is 132 inches again.

Adding up all four sides, we get:

216 + 132 + 216 + 132 = 696 inches

So the perimeter of the floor in the scale drawing is 696 inches.

Can you get the perimeter in the drawing?

Yes, to get the perimeter of the floor in the scale drawing, we need to divide the actual perimeter (696 inches) by the scale factor (2 feet/inch):

696 inches รท 2 feet/inch = 348 inches

Therefore, the perimeter of the floor in the scale drawing is 348 inches.

The volume of water in a reservoir decreases 21,000 cubic yards over 3 months period what is the average change in the volume per month

To find the average change in the volume per month, we can divide the total change in volume by the number of months:

Average change per month = Total change / Number of months

In this case, the total change in volume is a decrease of 21,000 cubic yards, and the number of months is 3:

Average change per month = -21,000 cubic yards / 3 months

Simplifying:

Average change per month = -7,000 cubic yards/month

Therefore, the average change in the volume per month is a decrease of 7,000 cubic yards.

No it's not correct whats the right answer please?