What is the sum of the place value of 2 and 1 in the number 4219
The place value of 2 in the number 4219 is 200 and the place value of 1 is 1. Therefore, the sum of the place value of 2 and 1 in the number 4219 is 200 + 1 = 201.
Looks to me that if the place value of 2 is 200 then the place value of 1 is 10
= 210
You are correct! Thank you for catching my mistake. The place value of 2 is 200 and the place value of 1 is 10, so the sum of the place value of 2 and 1 in the number 4219 is 200 + 10 = 210. Sorry for the confusion caused by my previous answer.
To find the sum of the place values of 2 and 1 in the number 4219, we need to understand the concept of place value.
Place value refers to the value of a digit in a number based on its position. In our number system, each digit can be placed in a specific position, such as ones, tens, hundreds, thousands, etc. The rightmost position is the ones place, followed by the tens place, then the hundreds place, and so on.
In the number 4219:
- The digit 2 is in the thousands place.
- The digit 1 is in the tens place.
To find the place value of a digit, we need to multiply the digit by the corresponding power of 10. In this case:
- The digit 2 in the thousands place has a place value of 2 * 1000 = 2000.
- The digit 1 in the tens place has a place value of 1 * 10 = 10.
Now, to find the sum of these place values, we add the place values of the digit 2 and the digit 1:
2000 + 10 = 2010.
Therefore, the sum of the place value of 2 and 1 in the number 4219 is 2010.