When this 3-digit number is rounded to the nearest hundred it rounds down to 600. The digit in the ones place is the third odd number that you count beginning with 1. The sum of the digits is 13 what is the number?

between 600 and 649

ends with 5
6?5
6 + ? + 5 = 13
How about 625 ?

I am a two-digit number but less than 40?

What am l?

1. rounds down to 600 = 601 - 649

2. The digit in the ones place is the third odd number that you count beginning with 1. = 605
3. The sum of the digits is 13

Take it from there.

To solve this problem, let's break it down step by step:

Step 1: Understand the given information
We are given that when this 3-digit number is rounded to the nearest hundred, it rounds down to 600. This means the 3-digit number is between 600 and 699.
We are also told that the digit in the ones place is the third odd number that you count beginning with 1. So, the ones digit is 5.

Step 2: Determine the possible values for the tens and hundreds digits
Since the number is rounded down to 600, the tens and hundreds digits can only be between 0 and 5. We need to find the possible values for these digits.

Step 3: Find the possible combinations and sum of the digits
We know that the sum of the digits is 13, so we can find all the possible combinations of tens and hundreds digits that result in a sum of 13.

Possible combinations:
- Hundred digit = 5, Tens digit = 2, Ones digit = 5 (Sum = 5 + 2 + 5 = 12)
- Hundred digit = 4, Tens digit = 3, Ones digit = 5 (Sum = 4 + 3 + 5 = 12)

Step 4: Find the number
Given that the number should have a ones digit of 5 and the possible combinations from step 3, the number is 425.

Please, I need help on this question!