How many atoms of al are present in 2.32g of al
To calculate the number of atoms of Al present in 2.32g of Al, we need to use Avogadro's number and the molar mass of aluminum.
The molar mass of Al is 26.98 g/mol, which means that one mole of Al contains 6.022 x 10^23 atoms.
We can use the following steps:
1. Calculate the number of moles of Al in 2.32g:
mass of Al / molar mass of Al = 2.32g / 26.98 g/mol = 0.0859 mol
2. Calculate the number of atoms in 0.0859 mol of Al:
number of atoms = 0.0859 mol x 6.022 x 10^23 atoms/mol = 5.18 x 10^22 atoms
Therefore, there are approximately 5.18 x 10^22 atoms of Al present in 2.32g of Al.
To calculate the number of atoms of Al (aluminum) present in 2.32 g of Al, you need to follow these steps:
Step 1: Find the molar mass of Al.
The molar mass of Al is 26.98 g/mol (grams per mole). This value represents the mass of one mole of Al.
Step 2: Calculate the number of moles of Al.
To find the number of moles of Al, divide the given mass (2.32 g) by the molar mass (26.98 g/mol):
Number of moles = mass / molar mass
Number of moles = 2.32 g / 26.98 g/mol
Using a calculator, you will get:
Number of moles ≈ 0.086 mol (rounded to three decimal places).
Step 3: Use Avogadro's number to calculate the number of atoms.
Avogadro's number, 6.022 x 10^23, represents the number of entities (atoms, molecules, etc.) in one mole.
Number of atoms = number of moles x Avogadro's number
Number of atoms = 0.086 mol x 6.022 x 10^23
Using a calculator, you will get:
Number of atoms ≈ 5.20 x 10^22 atoms (rounded to two significant figures).
Therefore, there are approximately 5.20 x 10^22 atoms of Al present in 2.32 g of Al.
To determine the number of atoms of Al (aluminum) present in 2.32g of Al, we need to use the concept of Avogadro's number and molar mass.
First, let's find the molar mass of aluminum. The atomic mass of Al is approximately 26.98 g/mol.
Now, we can set up a proportion to find the number of moles of Al:
Molar mass of Al (g/mol) / 1 mole = 2.32g / X moles
Rearranging the equation:
X moles = (2.32g * 1 mole) / molar mass of Al
X moles = (2.32g * 1 mole) / 26.98 g/mol
Calculating:
X moles ≈ 0.086 mol
Since 1 mole of any substance contains Avogadro's number of atoms (approximately 6.022 x 10^23 atoms), we can now find the number of atoms of Al in 2.32g:
Number of Al atoms = (0.086 mol) * (6.022 x 10^23 atoms/mol)
Calculating:
Number of Al atoms ≈ 5 x 10^22 atoms
Therefore, there are approximately 5 x 10^22 atoms of Al in 2.32g of Al.