Suppose 10 atoms of carbon (C) react with 20 atoms of oxygen (O) to form 10 molecules of carbon dioxide (C*O_{2}) . According to the law of conservation of matter, how many atoms are present in this reaction? (1 point)
30
O 20
O 10
O 15
To determine the number of atoms present in this reaction, we need to consider the number of atoms in each molecule involved.
Given that 10 molecules of carbon dioxide (CO2) are formed, we know that there are:
10 molecules * 1 atom of carbon per molecule = 10 atoms of carbon.
Since the reactants are 10 atoms of carbon (C) and 20 atoms of oxygen (O), the total number of atoms present in the reaction is:
10 atoms of carbon + 20 atoms of oxygen = 30 atoms.
Therefore, the correct answer is:
30
According to the law of conservation of matter, the number of atoms present before and after the reaction must be the same.
In this reaction, 10 atoms of carbon (C) combine with 20 atoms of oxygen (O) to form 10 molecules of carbon dioxide (C*O_{2}).
In each molecule of carbon dioxide, there is one atom of carbon and two atoms of oxygen. So, in 10 molecules of carbon dioxide, there are 10 atoms of carbon and 20 atoms of oxygen.
Therefore, the total number of atoms in this reaction is 10 atoms of carbon + 20 atoms of oxygen = 30 atoms.
The correct answer is 30.
To determine the number of atoms present in this reaction, we need to consider the balanced chemical equation for the reaction:
10C + 20O -> 10C*O2
From the equation, we can see that for every 10 atoms of carbon (C) and 20 atoms of oxygen (O), 10 molecules of carbon dioxide (C*O2) are formed.
Since each carbon dioxide molecule contains 1 carbon atom and 2 oxygen atoms, the total number of carbon atoms in the reaction is 10 x 1 = 10.
And the total number of oxygen atoms in the reaction is 10 x 2 = 20.
Therefore, in this reaction, there are 10 carbon atoms and 20 oxygen atoms.