Calculate the mass of silver deposited when 0.2A of electricity is passed through a silver chloride solution of 2 hours . Given that the chemical of silver is 0.000098g/c
10000
Your final statement of "Given that the chemical of silver is 0.000098g/c" is not a complete sentence and you've omitted a word so NOT using that number of 9.8E-5 I will work the problem using the standard method.
Coulombs = amperes x seconds
C = 0.2A x 2 hours x 60 min/hr x 60 sec/min = 1440
96,485 coulombs will deposit 107.88 g Ag.
Then 107.88 x (1440/96,485) = ? g Ag deposited.
If you care to explain that sentence I will try to use it.