10.5grams of zinc trioxocarbonate (iv)we're treated very strongly to a constant mass and the residue treated with excess hydrochloric acid. Calculate the mass of zinc chloride that would be obtained.
The International Union of Pure and Applied Chemistry (IUPAC) does not recognize the name you have given to ZnCO3. Zinc carbonate is a recognized by IUPAC.
ZnCO3 + heat --> ZnO + CO2, then
ZnO + 2HCl ==> ZnCl2 + H2O
mols ZnCO3 initially = g/molar mass = 10.5/125.4 = 0.0837
Then Convert to moles ZnCl2 formed this way:
0.0837 moles ZnCO3 x (1 mol ZnO/1 mol ZnCO3) x (1 mol ZnCl2/1 mol ZnO) = 0.0837 mols ZnCl2.
gramsZnCl2 = moles ZnCl2 x molar mass ZnCl2 = ? g