10.5g of zinc trioxocarbonate (iv) were heated very strongly to a constant mass and the residue treated with excess hydrochloric acid calculate the mass of zinc chloride that would be obtained
Zinc = 165, carbon = 12, oxygen =16, hydrogen=1 chlorine =35.5
First I want to ask where you were told that the name for ZnCO3 is zinc trioxocarbonate(iv). That is a made up name and it is not sanctioned by IUPAC. If you made it up let me know. If a teacher told you let me know. If you read it in some journal, book, newsletter, let me know. Also, note that Zn is not 165
ZnCO3 ==> ZnO + CO2
ZnO + 2HCl ==> ZnCl2 + H2O
mols ZnCO3 = grams/molar mass = about 10.5/125 = about 0.084
Now convert to mols ZnCl2 using the coefficients in the balanced equation.
0.084 mols ZnCO3 x (1 mol ZnO/1 mol ZnCO3) x (1 mol ZnCl2/1 mol ZnO) = 0.084 x 1/1 x 1/1 = 0.084 mols ZnCl2
Then grams ZnCl2 = mols ZnCl2 x molar mass ZnCl2.
Post your work if you don't understand anything about this.
To calculate the mass of zinc chloride that would be obtained, we need to first determine the balanced equation for the reaction between zinc trioxocarbonate (IV) and hydrochloric acid.
The balanced equation for the reaction is as follows:
ZnCO3 + 2HCl → ZnCl2 + H2O + CO2
From the equation, we can see that one mole of zinc trioxocarbonate (IV) reacts with two moles of hydrochloric acid to produce one mole of zinc chloride.
To calculate the mass of zinc chloride produced, we will use the following steps:
Step 1: Determine the molar mass of zinc trioxocarbonate (IV):
ZnCO3 = (1 x Zn) + (1 x C) + (3 x O)
= (1 x 65) + (1 x 12) + (3 x 16)
= 65 + 12 + 48
= 125 g/mol
Step 2: Convert the given mass of zinc trioxocarbonate (IV) to moles:
10.5 g / 125 g/mol = 0.084 mol
Step 3: Use the balanced equation to determine the moles of zinc chloride produced:
1 mole of ZnCO3 produces 1 mole of ZnCl2
0.084 mol of ZnCO3 produces 0.084 mol of ZnCl2
Step 4: Convert the moles of zinc chloride to mass:
0.084 mol x 65 g/mol = 5.46 g
Therefore, the mass of zinc chloride that would be obtained is 5.46 grams.
To calculate the mass of zinc chloride obtained, we need to determine the molar mass of zinc trioxocarbonate (IV) [ZnCO3].
First, let's calculate the molar mass of zinc trioxocarbonate (IV):
Zinc (Zn) = 165 g/mol
Carbon (C) = 12 g/mol
Oxygen (O) = 16 g/mol
Since there are three oxygen atoms in zinc trioxocarbonate, we multiply the molar mass of oxygen by 3:
3 x 16 g/mol = 48 g/mol
Now, sum up the molar masses of zinc, carbon, and oxygen:
165 g/mol + 12 g/mol + 48 g/mol = 225 g/mol
Next, let's calculate the number of moles of zinc trioxocarbonate used:
Given mass of zinc trioxocarbonate = 10.5 g
Number of moles = given mass / molar mass
Number of moles of zinc trioxocarbonate = 10.5 g / 225 g/mol
Now, the residue is treated with excess hydrochloric acid, which reacts with the zinc trioxocarbonate to form zinc chloride:
ZnCO3 + 2HCl -> ZnCl2 + CO2 + H2O
From the balanced equation, we can see that for every one mole of zinc trioxocarbonate, we get two moles of zinc chloride. Therefore, the number of moles of zinc chloride formed is twice the number of moles of zinc trioxocarbonate used.
Number of moles of zinc chloride = 2 x (10.5 g / 225 g/mol)
Finally, let's calculate the mass of zinc chloride obtained:
Mass of zinc chloride = number of moles of zinc chloride x molar mass of zinc chloride
To calculate the molar mass of zinc chloride:
Zinc (Zn) = 165 g/mol
Chlorine (Cl) = 35.5 g/mol
Molar mass of zinc chloride = 165 g/mol + 35.5 g/mol
Now, substitute the values to calculate the mass of zinc chloride:
Mass of zinc chloride = (2 x (10.5 g / 225 g/mol)) x (165 g/mol + 35.5 g/mol)
After performing the calculations, the resulting mass of zinc chloride obtained can be obtained.