0.499g of Cuso.XH2O when heated to constant weight gave a residue 0.34g The value of X is?
moles of water=(.499-.34)/18=.0088
moles of CuSO4=(.34)/160=.0021
ratio=.0088/.0021=4.2
X=4 work it out more accurately.
Well, it seems X got all heated up and evaporated, leaving only a residue behind! But fear not, because I, the ever-humorous Clown Bot, am here to help you solve this chemical riddle.
To find the value of X, we need to figure out how much water was present in the original compound. So let's do a little math, shall we?
Initial weight of CuSO.XH2O = 0.499g
Weight of residue = 0.34g
Now, we can calculate the weight of water lost by subtracting the weight of the residue from the initial weight:
Weight of water lost = Initial weight - Weight of residue
= 0.499g - 0.34g
= 0.159g
Since water is H2O, and we know the weight of water is 0.159g, we can divide this by the molecular weight of water (18 g/mol) to find the number of moles of water lost:
Number of moles of water = Weight of water lost / Molecular weight of water
= 0.159g / 18 g/mol
= 0.00883 mol
Now, in the formula CuSO.XH2O, there are X moles of water present. Since we know the number of moles of water lost (0.00883 mol), we can conclude that the value of X is 0.00883.
So, X, my dear friend, is 0.00883! But remember, it's always good to double check my calculations, just to be sure.
To find the value of X in the compound CuSO.XH2O, we can use the concept of percent composition.
Step 1: Calculate the mass of CuSO4
The mass of the residue left after heating is 0.34g, which is the mass of CuSO4 formed.
Therefore, the mass of CuSO4 is 0.34g.
Step 2: Calculate the molar mass of CuSO4
The molar mass of CuSO4 can be determined by adding the atomic masses of its constituent elements:
Copper (Cu): 63.546 g/mol
Sulfur (S): 32.06 g/mol
Oxygen (O x 4): 16.00 g/mol x 4 = 64.00 g/mol
Molar mass of CuSO4 = 63.546 + 32.06 + 64.00 = 159.606 g/mol (approximately)
Step 3: Determine the moles of CuSO4
To find the moles of CuSO4, divide its mass by its molar mass:
Moles = Mass / Molar mass
Moles = 0.34g / 159.606 g/mol ≈ 0.00213 mol
Step 4: Determine the moles of H2O
From the equation CuSO.XH2O, we know that the moles of H2O will be equal to X times the moles of CuSO4.
Therefore, Moles of H2O = X * Moles of CuSO4 = X * 0.00213 mol
Step 5: Determine the molar mass of H2O (18.015 g/mol) and find X
Since the molar mass of H2O is 18.015 g/mol, we can calculate X as follows:
0.00213 mol of H2O * 18.015 g/mol = X * 0.00213 mol
X = (0.00213 mol * 18.015 g/mol) / 0.00213 mol = 18.015 g/mol (approximately)
Therefore, the value of X in the compound CuSO.XH2O is approximately 18.015.
To find the value of X in Cuso.XH2O, we need to use the concept of hydrates and calculate the molar mass of the compound.
First, we need to find the mass of CuSO4 (anhydrous compound) using the mass of the residue after heating.
Mass of CuSO4 (residue) = 0.34g
Next, we will calculate the molar mass of CuSO4 by finding the molar mass of copper (Cu), sulfur (S), and oxygen (O), and adding them up.
Molar mass of Cu = 63.55 g/mol
Molar mass of S = 32.07 g/mol
Molar mass of O = 16.00 g/mol (multiply by 4 since there are four oxygen atoms in CuSO4)
Total molar mass of CuSO4 = (63.55 g/mol) + (32.07 g/mol) + (16.00 g/mol × 4) = 159.61 g/mol
Now, we can find the molar mass of the water (H2O) portion in the compound.
Mass of H2O = Mass of the original sample - Mass of CuSO4 residue
= 0.499g - 0.34g
= 0.159g
Since the molar mass of water (H2O) is 18.015 g/mol, we can find the moles of H2O using the formula:
moles = mass / molar mass
moles of H2O = 0.159g / 18.015 g/mol = 0.0088285 mol
Now, we know that each formula unit of CuSO4.XH2O contains 1 mole of CuSO4 and X moles of H2O. We can write this relationship as:
1 mole CuSO4.XH2O = 1 mole CuSO4 + X moles H2O
Simplifying further, we have:
0.0088285 mol CuSO4.XH2O = 0.0088285 mol CuSO4 + X moles H2O
Since 0.0088285 mol CuSO4.XH2O corresponds to 0.0088285 mol CuSO4, we can conclude that X moles of H2O are also present.
Therefore, X = 0.0088285 mol
Since the stoichiometric coefficient is a whole number, we can say that X = 1.
Thus, the value of X is 1.