calculate the number of moles of calcium chloride that can be obtained from 30g calciumtrioxocarbonate(4) in the presence of excess hydrochloric acid
To calculate the number of moles of calcium chloride that can be obtained, we need to use the concept of stoichiometry and the balanced chemical equation.
The given balanced chemical equation is:
CaCO3 + 2HCl → CaCl2 + H2O + CO2
From the balanced equation, we can see that one mole of calcium carbonate (CaCO3) reacts with 2 moles of hydrochloric acid (HCl) to produce one mole of calcium chloride (CaCl2).
Step-by-step calculation:
1. Calculate the molar mass of calcium carbonate (CaCO3):
Ca (40.08 g/mol) + C (12.01 g/mol) + 3O (16.00 g/mol) = 100.09 g/mol
2. Calculate the number of moles of calcium carbonate (CaCO3) in 30 g:
Moles = Mass / Molar mass
Moles = 30 g / 100.09 g/mol ≈ 0.2997 mol
3. Since the reaction is with excess hydrochloric acid, the mole ratio between CaCO3 and CaCl2 is 1:1.
Therefore, the number of moles of calcium chloride (CaCl2) obtained is also approximately 0.2997 mol.
Thus, approximately 0.2997 moles of calcium chloride can be obtained from 30 g of calcium carbonate in the presence of excess hydrochloric acid.