Calculate the mass of calcium chloride to make 0.2M calcium chloride solution
It all depends upon how much 0.2 M solution you want to make. You want 100 mL, 500 mL, 5 L? Let's say you want 200 mL.
Ask how many moles do I need for this soltion? That's
M x L = 0.2 M x 0.200 = 0.04 moles.
Then grams = moles x molar mass = 0.04 x molar mass CaCl2. You can figures molar mass. Ca = 40.078 + 2*35.453 = ?
Post your work if you get stuck.
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Now, onto your question. To calculate the mass of calcium chloride needed to make a 0.2M solution, we need to use the formula:
Molarity(M) = (moles of solute) / (volume of solution in liters)
First, we need to convert the desired molarity to moles of solute. Since the equation for calcium chloride is CaCl2, we know that one mole of calcium chloride consists of one mole of calcium (Ca) and two moles of chlorine (Cl), for a total of three moles of ions. Therefore, to prepare a 0.2M calcium chloride solution, we will have 0.2 moles of ions per liter.
So, to get the mass, we need to know the molar mass of calcium chloride. The molar mass of CaCl2 is approximately 111 grams/mol. Therefore:
Mass = moles x molar mass
Mass = 0.2 mol x 111 g/mol
Mass = 22.2 grams
Hence, to make a 0.2M calcium chloride solution, you would need approximately 22.2 grams of calcium chloride.
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To calculate the mass of calcium chloride needed to make a 0.2M solution, you will need to know the molecular weight of calcium chloride (CaCl2).
The molecular weight of calcium chloride (CaCl2) is 110.98 g/mol.
A 0.2M solution means that there are 0.2 moles of calcium chloride dissolved in 1 liter of solution.
First, convert the molarity (0.2M) to moles:
0.2 moles/L * 1 L = 0.2 moles
Now, calculate the mass using the equation:
Mass (g) = Moles * Molecular Weight
Mass (g) = 0.2 moles * 110.98 g/mol
Mass (g) = 22.196 g
Therefore, you would need approximately 22.196 grams of calcium chloride to make a 0.2M calcium chloride solution.
To calculate the mass of calcium chloride needed to make a 0.2M solution, we need to know the molar mass of calcium chloride and the volume of the solution.
The molar mass of calcium chloride (CaCl2) is the sum of the atomic masses of calcium (Ca) and two chlorine atoms (Cl), which are:
Ca: 40.08 g/mol
Cl: 35.45 g/mol (since there are two Cl atoms, the molar mass is multiplied by 2)
So, the molar mass of CaCl2 is:
(1 * 40.08 g/mol) + (2 * 35.45 g/mol) = 110.98 g/mol
A 0.2M solution means that there are 0.2 moles of calcium chloride per liter (L) of solution. To find the mass of calcium chloride needed for a given volume, we can use the following equation:
Mass (g) = Molar mass (g/mol) * Moles (mol)
Since we want to find the mass in grams, we need to convert the given volume to liters. Let's assume we want to prepare 1 liter of the solution:
Volume (L) = 1 L
Now, we can calculate the mass of calcium chloride:
Mass (g) = 0.2 mol/L * 110.98 g/mol * 1 L
= 22.196 g
Therefore, you will need approximately 22.196 grams of calcium chloride to make a 0.2M solution in 1 liter of water.