# The bearing of Teta from p is 250 and the bearing of r from q is 160 degree. If q is equidistant from p and r , find the bearing of r from p.

## first, it's theta, not Teta

second, I think you mean r or q, and not "Teta"

If the bearing of q from p is 250° then you have an isosceles triangle pqr so r is directly south of p: a bearing of 180°

If you meant that the bearing of r from p is 250°, then you need to adjust things. Post your work if you get stuck.

## To find the bearing of r from p, we need to consider the bearings of Teta from p and r from q.

Given that the bearing of Teta from p is 250 degrees and the bearing of r from q is 160 degrees, we can determine the angle between the lines connecting p to q and q to r.

Since q is equidistant from p and r, the line connecting p to q is the same as the line connecting q to r. Therefore, the angle between these lines is equal to the sum of the bearings.

To find the bearing of r from p, we subtract the angle between the lines from 360 degrees.

Let's calculate:

Angle between the lines = (360 - 250) + 160

= 110 + 160

= 270 degrees

Therefore, the bearing of r from p is 270 degrees.

## To find the bearing of point r from point p, we need to know the bearings of point p from a common point (let's call it x), and the bearing of point r from the same point x.

However, based on the information given in the question, we only know the bearings of point Teta from point p (250 degrees) and the bearing of point r from point q (160 degrees).

Without additional information, it is not possible to determine the bearing of point r from point p.