The bearing of Q from P is 300 degrees and the bearing of R from Q is 210 degrees. If Q is equidistance from P and R, find the bearing of R from P.?

Question

Create an image representing a geographical scenario where there are three different points, labeled P, Q, and R. Imagine P is situated at the origin of a circular compass rose. Place Q such that it lies on the 300-degree mark of the compass from P. Then position point R, such that it lies on the 210-degree mark from Q. Emphasize the idea that Q is equidistant from both P and R by making the distance between them equal. It's equally important not to include any text within the image.

The bearing of Q from P is 300 degrees and the bearing of R from Q is 210 degrees. If Q is equidistance from P and R, find the bearing of R from P.?

Answer 1

A man start from a point A and walks 1000m on a bearing of 025°. How far north is he from his starting point.?

Answer 2

R's bearing from P is 270-θ, where

tanθ = √2/(1+√3)

Answer 3

your 2nd question:

cos 25 = y/1000
y = 1000cos25 = ....

Answer 4

To find the bearing of R from P, we need to add the bearings of Q from P and R from Q.

Given that the bearing of Q from P is 300 degrees and the bearing of R from Q is 210 degrees, we can proceed as follows:

1. Start with the bearing of Q from P, which is 300 degrees.

2. Add the bearing of R from Q, which is 210 degrees.

300 degrees + 210 degrees = 510 degrees

3. The resulting value, 510 degrees, is the bearing of R from P.

Therefore, the bearing of R from P is 510 degrees.