20g of zinc trioxocarbonate IV were heated and the residue treated with excess hcl acid . Calculate the mass of ZNCL that will be obtained
ZnCO3 + heat ==>ZnO + CO2
ZnO + 2HCl ==> ZnCl2 + H2O
1. Write and balance the equations. Done above.
2. mols ZnCO3 = grams/molar mass = 20/125.4 = 0.159
3. Convert mols ZnCO3 to mols ZnCl2 as follows:
0.159 mols ZnCO3 x (1 mol ZnO/1 mol ZnCO3) x (1 mol ZnCl2/1 mol ZnO) = 0.159 (1/1)(1/1) = 0.159 mols ZnCl2.
4. Then grams ZnCl2 = mols ZnCl2 x molar mass ZnCl2 = ?
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