A metal X with relative atomic mass 56 forms an oxide with formular X2O3. how many grams of metal will combine with 10g of oxygen? (O=16)
To determine the number of grams of metal that will combine with 10g of oxygen, we first need to find the molar mass of the metal X.
Given that the relative atomic mass (RAM) of metal X is 56, this value represents the molar mass of one mole of metal X. Therefore, the molar mass of metal X is 56 g/mol.
Next, let's determine the molar mass of the oxide X2O3.
The molar mass of oxygen (O) is 16 g/mol, and there are three oxygen atoms in one molecule of X2O3. So, the molar mass of the oxide X2O3 can be calculated as follows:
Molar mass of X2O3 = (2 × molar mass of X) + (3 × molar mass of O)
= (2 × 56 g/mol) + (3 × 16 g/mol)
= 112 g/mol + 48 g/mol
= 160 g/mol
Now, we can use the molar mass of the oxide X2O3 to find the grams of metal that will combine with 10g of oxygen.
Since the molecular formula of X2O3 indicates that two moles of metal combine with three moles of oxygen, we need to compare the molar ratio of oxygen to metal.
Based on the molar ratio:
3 moles of oxygen = 160 g
1 mole of oxygen = 160 g / 3
10 g of oxygen = (10 g × 1 mole) / (160 g / 3)
= 0.1875 moles
Now, we can find the grams of metal required to combine with 0.1875 moles of oxygen.
1 mole of metal X = 56 g
0.1875 moles of metal X = 56 g × 0.1875 moles
= 10.5 g
Therefore, 10 grams of oxygen will combine with 10.5 grams of metal X.