10.5g of zinc trioxocarbonate(iv), we're heated very strongly to a constant mass and resdiue treated with excess hydrochloric acid. Calculate the mass of zinc chloride that would be obtained
(Zn=16, C=12, O=16, h=1, Cl=35.5)
The correct IUPAC name for ZnCO3 is zinc carbonate.
...................ZnCO3 + heat ==> ZnO + CO2
ZnO + 2HCl ==> ZnCl2 + H2O
mols ZnCO3 = g/molar mass = 10.5 g/approx 125 = about 0.084
0.084 mols ZnCO3 will produce 0.085 mols ZnO and that will produce 0.084 mols ZnCl2.
grams ZnCl2 = mols ZnCl2 x molar mass ZnCl2 = ?
Note: I have estimated molar masses and estimated the calculations so you should recalculate all of the above. Post your work if you get stuck.
I got 7.7g. Is it correct?
To calculate the mass of zinc chloride that would be obtained, we need to first determine the chemical reaction that occurs when zinc trioxocarbonate (ZnCO3) is heated and treated with hydrochloric acid (HCl).
The balanced chemical equation for the reaction between zinc trioxocarbonate and hydrochloric acid is:
ZnCO3 + 2HCl → ZnCl2 + CO2 + H2O
From the equation, we can see that one mole of zinc trioxocarbonate reacts with two moles of hydrochloric acid to produce one mole of zinc chloride, one mole of carbon dioxide, and one mole of water.
1 mole of ZnCO3 → 1 mole of ZnCl2
To calculate the mass of zinc chloride produced, we need to calculate the number of moles of zinc trioxocarbonate. Given that the mass of zinc trioxocarbonate is 10.5g and the molar mass is 65.37 g/mol (Zn=65.38g/mol + C=12.01g/mol + 3O=3x16.00g/mol), we can calculate the number of moles as follows:
moles of ZnCO3 = mass of ZnCO3 / molar mass of ZnCO3
moles of ZnCO3 = 10.5g / 65.37 g/mol
Now let's calculate the moles of zinc chloride by using mole ratios from the balanced chemical equation. The mole ratio between ZnCO3 and ZnCl2 is 1:1. Therefore, the number of moles of ZnCl2 produced will be the same as the number of moles of ZnCO3.
moles of ZnCl2 = moles of ZnCO3
Next, we need to calculate the mass of zinc chloride using the calculated moles of ZnCl2 and the molar mass of ZnCl2, which is 65.38 g/mol (Zn=65.38g/mol + 2Cl=2x35.5g/mol):
mass of ZnCl2 = moles of ZnCl2 x molar mass of ZnCl2
mass of ZnCl2 = moles of ZnCl2 x 65.38 g/mol
Substituting the value of moles of ZnCl2 (which is equal to the moles of ZnCO3), we can calculate the mass of zinc chloride.
To calculate the mass of zinc chloride obtained, you would need to determine the chemical equation for the reaction between zinc trioxocarbonate(IV) (ZnCO3) and hydrochloric acid (HCl). From the equation, you can calculate the stoichiometry, which relates the relative amounts of reactants and products.
The balanced chemical equation for the reaction is as follows:
ZnCO3 + 2HCl → ZnCl2 + H2O + CO2
From the equation, you can see that 1 mole of ZnCO3 reacts with 2 moles of HCl to produce 1 mole of ZnCl2.
First, convert the mass of zinc trioxocarbonate(IV) to moles. To do this, divide the given mass of 10.5g by the molar mass of ZnCO3:
Molar mass of ZnCO3 = (Zn = 65.38) + (C = 12.01) + (3O = 3 x16.00)
= 65.38 + 12.01 + 48.00
= 125.39 g/mol
Moles of ZnCO3 = 10.5g / 125.39 g/mol
≈ 0.0837 mol
According to the balanced chemical equation, 1 mole of ZnCO3 reacts to produce 1 mole of ZnCl2. Therefore, the moles of ZnCl2 obtained would also be 0.0837 mol.
To calculate the mass of ZnCl2, multiply the moles of ZnCl2 by its molar mass:
Molar mass of ZnCl2 = (Zn = 65.38) + (2Cl = 2 x 35.5)
= 65.38 + 71.0
= 136.38 g/mol
Mass of ZnCl2 = 0.0837 mol x 136.38 g/mol
≈ 11.40 g
Therefore, the mass of zinc chloride obtained would be approximately 11.40 grams.