Calculate the number of mole from calcium chloride (ca cl2) that canbe obtaned 60g of calciumtrioxo corbonata )(ca co3) presence of hydrochlorice acid (i +cl) (ca =40c=12, 0=16cl=35.5)
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To calculate the number of moles of calcium chloride (CaCl2) that can be obtained from 60g of calcium trioxocarbonate (CaCO3) in the presence of hydrochloric acid (HCl), you first need to write and balance the chemical equation for the reaction. The balanced equation is:
CaCO3 + 2HCl → CaCl2 + CO2 + H2O
From the balanced equation, you can see that one mole of calcium trioxocarbonate (CaCO3) reacts with two moles of hydrochloric acid (HCl) to produce one mole of calcium chloride (CaCl2).
Now, you can calculate the molar mass of CaCO3 and find the number of moles in 60g of CaCO3.
Molar mass of CaCO3:
Ca = 40g/mol
C = 12g/mol
O = 16g/mol (3 oxygen atoms in CaCO3)
Molar Mass of CaCO3 = (40g/mol) + (12g/mol) + (16g/mol x 3) = 100g/mol
To find the number of moles, you can use the formula:
Number of Moles = Mass / Molar Mass
Number of Moles of CaCO3 = 60g / 100g/mol = 0.6 mol
Since one mole of CaCO3 reacts with one mole of CaCl2, the number of moles of CaCl2 that can be obtained is also 0.6 mol.