222
Ra successfully looses 3 alpha particles and further 2 beta particles
Write out the formula of n
88?
To determine the atomic number (n) of an element, you need to consider the number of protons in its nucleus. In this case, Radon (Ra) initially has an atomic number of 88.
The given information states that Ra loses 3 alpha particles and 2 beta particles. An alpha particle consists of 2 protons and 2 neutrons, while a beta particle refers to the emission of an electron or a positron.
When an alpha particle is emitted, the atomic number decreases by 2 since 2 protons are lost from the nucleus. So, if Ra loses 3 alpha particles, the atomic number would decrease by 2 x 3 = 6.
When a beta particle is emitted, the atomic number increases by 1 since an electron or a positron carries away one unit of negative charge, effectively increasing the number of protons by 1. If Ra loses 2 beta particles, the atomic number would increase by 2 x 1 = 2.
Therefore, to calculate the new atomic number (n), subtract the decrease due to the alpha particles (6) and add the increase due to the beta particles (2) to the initial atomic number of Ra (88):
n = 88 - 6 + 2
= 84 + 2
= 86
Hence, the formula for the atomic number (n) for the new element after Ra loses 3 alpha particles and 2 beta particles is 86.