Hi, Im trying to do my math corrections and I cannot figure out 3!. That was explained no where in my lessons. Can someone please explain the steps? I used my calculator and mathway.com but mathway.com makes me pay for the steps. Please help me:)
What is the problem?
by definition n! = 1 x 2 x 3 x .... x n
so 3! = 1 x 2 x 3 = 6
n has to be a positive integer, with the special definition of 0! = 1
most "scientific" calculator have the n! function
on mine it is the 2nd function of 4 on the number pad,
check to see if you see n! anywhere
On mine, to get 8!, I would press:
8
2ndF
4
=
and it would give me 40320
check: 1x2x3x4x5x6x7x8 = 40320
ok thanks
Of course! I'd be happy to help you understand how to calculate 3!. The exclamation mark in mathematics denotes the factorial function. The factorial of a number is the product of all positive integers less than or equal to that number.
To calculate 3!, you need to multiply all positive integers less than or equal to 3, which are 3, 2, and 1. Let's go through the steps together:
1. Start with the given number, which is 3.
2. Multiply 3 by the next smaller positive integer, which is 2. (3 * 2 = 6)
3. Multiply the previous result by the next smaller positive integer, which is 1. (6 * 1 = 6)
So, 3! equals 6.
In general, n! (read as "n factorial") is calculated by multiplying all positive integers from 1 up to n. The notation can be understood as follows:
n! = n * (n-1) * (n-2) * ... * 3 * 2 * 1
If you encounter larger factorials, like 5! or 10!, simply follow the same steps by multiplying all positive integers up to the given number.
I hope this explanation helps you understand how to calculate factorials and solve your math problem. Let me know if you have any other questions!