When a (1.797x10^0) g sample of CuSO4 * 5H2O (Copper II Sulfate Pentahydrate) and NaCl was heated, a total sample of (2.74x10^-1) g of water was lost. What is the mass percent of hydrate in this sample? Give your answer in scientific notation with three significant figures.
How would you solve this?
To solve this problem, follow the steps below:
Step 1: Find the mass of water lost
Given that the total sample lost 2.74x10^-1 g of water, this value represents the mass of water lost.
Step 2: Find the mass of the anhydrous (without water) compound
Subtract the mass of water lost from the total sample mass to find the mass of the anhydrous compound.
Step 3: Calculate the mass percent of the hydrate
Divide the mass of the hydrate (CuSO4 * 5H2O) by the total sample mass and multiply by 100 to find the mass percent of the hydrate.
Now let's perform the calculations step by step:
Step 1: Find the mass of water lost
Water lost = 2.74x10^-1 g
Step 2: Find the mass of the anhydrous compound
Total sample mass = 1.797x10^0 g
Anhydrous compound mass = Total sample mass - Water lost
Anhydrous compound mass = 1.797x10^0 g - 2.74x10^-1 g
Step 3: Calculate the mass percent of the hydrate
Mass percent of hydrate = (Mass of hydrate / Total sample mass) x 100
Mass percent of hydrate = (Anhydrous compound mass / Total sample mass) x 100
Replace the values in the formula:
Mass percent of hydrate = (1.797x10^0 g - 2.74x10^-1 g) / (1.797x10^0 g) x 100
Mass percent of hydrate = (1.797 - 0.274) / 1.797 x 100
Mass percent of hydrate = 1.523 / 1.797 x 100
Mass percent of hydrate = 0.8477 x 100
Mass percent of hydrate = 84.77%
The mass percent of hydrate in this sample is 84.77%.
To solve this problem, we need to know the following:
1. The initial mass of the sample: 1.797 x 10^0 g
2. The mass of water lost: 2.74 x 10^-1 g
To find the mass percent of the hydrate, we need to calculate the mass of the hydrate and then divide it by the initial mass of the sample, and finally multiply by 100 to get the percentage.
To find the mass of the hydrate, we subtract the mass of water lost from the initial mass of the sample:
Mass of hydrate = Initial mass of sample - Mass of water lost
= (1.797 x 10^0 g) - (2.74 x 10^-1 g)
Now, we can calculate the mass percent of the hydrate:
Mass percent of hydrate = (Mass of hydrate / Initial mass of sample) x 100
Let's calculate it:
Mass percent of hydrate = ((1.797 x 10^0 g) - (2.74 x 10^-1 g) / (1.797 x 10^0 g)) x 100
= (1.523 x 10^0 g / 1.797 x 10^0 g) x 100
= 1.523 / 1.797 x 100
= 84.8
Therefore, the mass percent of hydrate in this sample is approximately 84.8%.