# CuSO4.xH2O

Determine the percent by mass of water in your sample of hydrated copper (II) sulfate. Show your calculations clearly.

My work.
i got 10% is that correct

## In one word, no.

You can calculate what you should get in the lab if you're doing a lab experiment.
molar mass CuSO4.5H2O = 249.7
molar mass 5H2O = about 90
Then (90/249.7)*100 = ?

## Well, it seems like you're doing some chemistry here! However, I'm afraid you haven't provided me with the value of 'x' in CuSO4.xH2O, which represents the number of water molecules attached to each copper (II) sulfate molecule.

To determine the percent mass of water in the sample, you need to compare the molar mass of water to the total molar mass of the hydrate.

First, calculate the molar mass of water (H2O) using the atomic masses of hydrogen (H) and oxygen (O), which are approximately 1 g/mol and 16 g/mol, respectively. Adding them up gives us a molar mass of 18 g/mol for water.

Now, let's say the molar mass of CuSO4 is M1, and we want to find the percent mass of water (H2O) in the hydrated form, CuSO4.xH2O. The molar mass of the entire compound can be denoted as M2.

The percent mass of water can be calculated using the formula:

% Mass of Water = [(x × M1) / M2] × 100

But without knowing the value of 'x', I'm unable to provide the correct answer. So, make sure you know the value of 'x' and plug it into the formula to find the percent mass accurately.

Keep up the good work, though!

## To determine the percent by mass of water in your sample of hydrated copper (II) sulfate, you need to calculate the mass of water and divide it by the total mass of the compound, then multiply by 100 to get the percentage.

First, you need to find the molar mass of CuSO4.xH2O. The molar mass of copper (II) sulfate (CuSO4) is 159.609 g/mol. The molar mass of water (H2O) is 18.015 g/mol.

Next, you need to determine the value of 'x' in CuSO4.xH2O. This is the number of water molecules associated with each copper (II) sulfate molecule. To find 'x', you can use the given information or experimental data. Since the value of 'x' is not provided in your question, let's assume it to be 'y' for now.

So, the molar mass of CuSO4.xH2O is 159.609 + 18.015*y g/mol.

Now, let's say you have a sample weighing 'm' grams. To find the mass of water in your sample, you need to multiply the molar mass of H2O by the value of 'y' (since there are 'y' water molecules associated with each CuSO4 molecule) and divide it by the molar mass of CuSO4.xH2O:

Mass of water = (18.015 * y * m) / (159.609 + 18.015 * y) grams

To calculate the percent by mass of water in your sample, divide the mass of water by the total mass of the compound (mass of CuSO4.xH2O) and multiply by 100:

Percent by mass of water = (Mass of water / Mass of CuSO4.xH2O) * 100

Now, substitute the given values and calculate:

Percent by mass of water = (Mass of water / (molar mass of CuSO4.xH2O * m)) * 100

Make sure to substitute the appropriate values for 'y,' 'm,' and any other variables provided in your question.

Based on your statement that you calculated the percent by mass of water in your sample to be 10%, it is not possible for me to confirm its correctness or provide further assistance without knowing the values you used for 'y' and 'm'. I recommend rechecking your calculations with the correct values and following the steps explained above to obtain an accurate answer.