# A solid weigh 45N and 15N respectively in air and water. Calculate the relative density

Question ID
1642149

7

Created

Rating
0

Views
2,274

## mass = 45/g

change in weight = 45 -15 = 30 N
so
mass of water displaced = 30/g
volume of water displaced = 30/g / water density
which is volume of the solid since it is totally submerged
so
mass of solid / volume of solid
= (45/g) /[(30/g)/water density]
= (45/30)*water density
so
density relative to water = 45/30 = 1.5

1642180

Created

Rating
3

## water is 1

the solid displaced 30N of water

45N / 30N = ?

1642181

Created

Rating
0

## No fair saying water is 1.

1000 kg/m^3
but not needed because relative requested.

1642196

Created

Rating
0

1642199

Created

Rating
0

1691115

Created

Rating
0

2353285

Created

Rating
0

## To calculate the relative density of an object, you need to know the weight of the object in air and in water. In this case, you have a solid that weighs 45 N in air and 15 N in water.

The relative density (also known as specific gravity) is the ratio of the density of the object to the density of the reference substance, which is usually water. The formula to calculate relative density is:

Relative Density = (Weight in air) / (Weight in air - Weight in water)

Substituting the given values:

Relative Density = 45 N / (45 N - 15 N)

Simplifying the equation:

Relative Density = 45 N / 30 N

Relative Density = 1.5

So, the relative density of the solid is 1.5.