A body weighs 0.30N in air. 0.25N when fully immersed in water and 0.27N in a liquid. Calculate the relative density of the liquid.
ur mom
Not correct
Well, it seems like that liquid has got a bit of a weight problem, doesn't it? Let's help it figure out its relative density!
Now, relative density is simply the ratio of the weight of an object in a particular liquid to the weight of that same object in water. In this case, the weight of the body in water is 0.25N, and the weight of the body in the liquid is 0.27N.
So, the relative density of the liquid can be calculated as follows:
Relative Density = Weight in Liquid / Weight in Water
Relative Density = 0.27N / 0.25N
And if we simplify that, we get:
Relative Density = 1.08
Voila! The relative density of the liquid is 1.08. But hey, don't tell the liquid that it's a bit denser than water, it might have a complex!
To calculate the relative density of the liquid, we need to use the concept of buoyancy.
Buoyancy is a force exerted by a fluid (liquid or gas) on an object immersed in it. It acts opposite to the direction of gravity and is equal to the weight of the fluid displaced by the object.
When the body is immersed in water, it experiences a buoyant force that reduces its weight. The difference between the weight in air and the weight in water is equal to the weight of the water displaced by the body.
In this case, the weight of the body in air is given as 0.30N, and the weight when fully immersed in water is 0.25N. The difference between these two weights is the weight of the water displaced:
Weight of water displaced = Weight in air - Weight in water
= 0.30N - 0.25N
= 0.05N
Now, we need to calculate the volume of water displaced. To do this, we can use the formula:
Volume of water displaced = Weight of water displaced / Density of water
The density of water is approximately 1000 kg/m³, which is equivalent to 9.8 N/m³ (since 1 kg = 9.8 N).
Volume of water displaced = 0.05N / 9.8 N/m³
≈ 0.0051 m³
Since the volume of water displaced is equal to the volume of the body, we can calculate the relative density of the liquid using the formula:
Relative Density = Density of liquid / Density of water
= Weight in liquid / (Volume of water displaced * Density of water)
The weight of the body in the liquid is given as 0.27N.
Relative Density = 0.27N / (0.0051 m³ * 9.8 N/m³)
≈ 0.27 / 0.04998
≈ 5.41
Therefore, the relative density of the liquid is approximately 5.41.
difference in water = 0.05 N
Archimedes says water force up = rho * g * V
1000 kg/ m^3 * 9.81 m/s^2 * V
so V = 0.05 / (1000 * 9.81 )
force up in magic fluid = 0.03 N
0.03 = rho * 9.81 * [0.05 / (1000 * 9.81 ) ]
so what is rho ?
for relative to water divide by 1000