Type in the two equations you used to solve the problem below and then state the values of x.
2x - 4 = 22
x = ?
2x - 4 = -22
x = ?
Can someone walk me through on how to find the values of x?
Oops, forgot to write the initial equation: |2x - 4| = 22
2x - 4 = 22 and 2x - 4 = -22
I assume you know how to solve these
I don't know how to solve those, that's why I asked if someone can walk me through the process of solving them.
2x-4 = 22
2x = 26
x = 13
same way for the other
To find the values of x in the given equations, we can use a method called algebraic manipulation. Let's solve the equations step by step.
Equation 1: 2x - 4 = 22
To isolate the variable x, we need to get rid of the constant term (-4) on the left side of the equation. We can do this by performing inverse operations.
Adding 4 to both sides of the equation:
2x - 4 + 4 = 22 + 4
2x = 26
Now, we want to isolate x. Since x is multiplied by 2, we can divide both sides of the equation by 2:
(2x)/2 = 26/2
x = 13
So, the solution to Equation 1 is x = 13.
Equation 2: 2x - 4 = -22
Similar to the previous equation, we will perform inverse operations to isolate the variable x.
Adding 4 to both sides of the equation:
2x - 4 + 4 = -22 + 4
2x = -18
Dividing both sides of the equation by 2:
(2x)/2 = -18/2
x = -9
Therefore, the solution to Equation 2 is x = -9.
In conclusion, the values of x for the given equations are x = 13 and x = -9.