Robert must read a few books from his home library. He read 4 out of 6 books from the top shelf, then 2 out of 3 books from the middle shelf and then 3 out of 6 books from the bottom shelf. In how many ways can Robert read the books, if different orders in which the books will be read count as different ways?
Reiny is partially correct. However, instead of using combinations you would use permuations. So it would be P(6,4)*P(3,2)*P(6,3), and that would leave you with the answer 259200.
To find the total number of ways Robert can read the books, we need to multiply the number of choices for each shelf together.
1. The number of ways he can read the books on the top shelf is 4 out of 6, which can be calculated as C(6, 4) = 6! / (4!(6-4)!) = 15.
2. The number of ways he can read the books on the middle shelf is 2 out of 3, which can be calculated as C(3, 2) = 3! / (2!(3-2)!) = 3.
3. The number of ways he can read the books on the bottom shelf is 3 out of 6, which can be calculated as C(6, 3) = 6! / (3!(6-3)!) = 20.
To find the total number of ways, we multiply these results together:
Total ways = 15 x 3 x 20 = 900 ways.
Therefore, Robert can read the books in 900 different ways.
To find the number of ways Robert can read the books, we can multiply the number of options for each shelf.
For the top shelf, Robert can choose 4 books out of 6. This can be done in C(6, 4) ways, which is calculated as (6!)/(4!(6-4)!) = 15 ways.
For the middle shelf, Robert can choose 2 books out of 3. This can be done in C(3, 2) = 3 ways.
For the bottom shelf, Robert can choose 3 books out of 6. This can be done in C(6, 3) = 20 ways.
To find the total number of ways, we multiply these values together:
15 * 3 * 20 = 900.
Therefore, Robert can read the books in 900 different ways.
First let's choose the books
top shelf = C(6,4) = 15
middle shelf = C(3,2) = 3
bottom shelf = C(6,3) = 20
so he can read 15x3x20 or 900 different combinations of 9 books
Now for each of the choices of 9 books, he can read them in 9! ways.
so the number of ways he can read the books
= 900(9!)
= 326,592,000
2nd interpretation:
He has a choice of 15 different groups of 4 books from the top shelf
these can be read in 15(4!) or 360 orders.
He has choice of 3 pairs of books from the middle, these can be read in 3(2!) or 6 ways
He has a choice of 30 triples of books from the bottom, which he can read in 30(3!) or 180
So the number of arrangement if he must follow the order top, middle bottom books
= 360(6)(180)
= 388,800
I would go with my first solution