Calculate the sum of all possible two - digit numbers using 3 and 4
list them, then add them up
148
To calculate the sum of all possible two-digit numbers using 3 and 4, we need to find all the possible combinations of these two numbers.
First, let's list all the possible tens digits: 3 and 4.
Now, let's list all the possible ones digits: 3 and 4.
Combining each tens digit with each ones digit, we get the following four possible two-digit numbers: 33, 34, 43, and 44.
To find the sum of these numbers, we can simply add them together:
33 + 34 + 43 + 44 = 154.
Therefore, the sum of all possible two-digit numbers using 3 and 4 is 154.
To calculate the sum of all possible two-digit numbers using 3 and 4, we need to find out all the possible combinations of these two digits.
Since a two-digit number can have a tens digit (the digit in the tens place) ranging from 1 to 9, and a ones digit (the digit in the ones place) ranging from 0 to 9, we can pair the digit 3 with all possible digits from 0 to 9 to form two-digit numbers. Similarly, we can pair the digit 4 with all possible digits from 0 to 9.
Here are all the possible combinations of the digits 3 and 4 to form two-digit numbers:
Combining 3 with 0-9: 30, 31, 32, 33, 34, 35, 36, 37, 38, 39
Combining 4 with 0-9: 40, 41, 42, 43, 44, 45, 46, 47, 48, 49
Now, we can calculate the sum of these numbers:
30 + 31 + 32 + 33 + 34 + 35 + 36 + 37 + 38 + 39 + 40 + 41 + 42 + 43 + 44 + 45 + 46 + 47 + 48 + 49
To simplify the calculation, we can use the formula to find the sum of an arithmetic series:
Sum = (n/2)(first term + last term)
In this case, the first term is 30, the last term is 49, and there are 20 terms (10 from 3 and 10 from 4). Plugging these values into the formula, we get:
Sum = (20/2)(30 + 49) = 10(79) = 790
So, the sum of all possible two-digit numbers using 3 and 4 is 790.