# If a cheetah is able to accelerate at 15.0 m/s2 from a stand still, what speed will it reach after 2.50 seconds?

## vf= a*t

## To find the speed the cheetah will reach after 2.50 seconds, you can use the formula for acceleration:

acceleration (a) = change in velocity (Δv) / time (t)

Rearranging the formula gives us the change in velocity:

Δv = a * t

Substituting the given values:

Δv = 15.0 m/s² * 2.50 s

Δv = 37.5 m/s

Therefore, the cheetah will reach a speed of 37.5 m/s after 2.50 seconds.

## To find the speed the cheetah will reach after 2.50 seconds, we can use the formula for acceleration:

\(v = u + at\)

where:

\(v\) is the final velocity,

\(u\) is the initial velocity (0 m/s as it starts from a standstill),

\(a\) is the acceleration (15.0 m/s²),

and \(t\) is the time taken (2.50 seconds).

Plugging in the values into the formula:

\(v = 0 + (15.0 \, \text{m/s}^2) \times (2.50 \, \text{s})\)

\(v = 0 + 37.5 \, \text{m/s}\)

Therefore, the cheetah will reach a speed of 37.5 m/s after 2.50 seconds.