a cyclist accelerates at a rate of 7.0m/s^2. how long will it take the cyclist to reach a speed of 18m/s? my answer is 2.5seconds. is this correct?
I get 2.571 , which would be
2.6 correct to one decimal place
the answer is 2.571. the 1 does not round up to turn the 7 to an 8. 2.57 is the correct answer. i have to do this same problem for chemistry.
To find the time it takes for the cyclist to reach a speed of 18 m/s, you can use the following formula:
v = u + at
Where:
v = final velocity (18 m/s)
u = initial velocity (0 m/s, assuming the cyclist starts from rest)
a = acceleration (7.0 m/s^2)
t = time
Rearranging the formula to solve for time (t):
t = (v - u) / a
Now plugging in the values:
t = (18 m/s - 0 m/s) / 7.0 m/s^2
t ≈ 2.571 seconds
So, the correct answer is approximately 2.571 seconds, rounded to the nearest thousandth.
To find out if your answer is correct, let's use the basic kinematic equation:
v = u + at
Where:
v = final velocity
u = initial velocity
a = acceleration
t = time
Given data:
u = 0 m/s (since the cyclist starts from rest)
a = 7.0 m/s^2
v = 18 m/s
Plugging in the values into the equation:
18 = 0 + 7.0t
Simplifying the equation:
18 = 7.0t
Now, solve for t:
t = 18 / 7.0
t ≈ 2.5714 seconds
So, it seems like your answer of 2.5 seconds is approximate. The precise answer is approximately 2.5714 seconds.