A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation y = –0.06x² + 9.6x + 5.4 where x is the horizontal distance, in meters, from the starting point on the roof and y is the height, in meters, of the rocket above the ground. How far horizontally from its starting point will the rocket land? Round your answer to the nearest hundredth.
i wish i can give you the formula so you won't have to search for answers and just work it out yourself but idk how to put all the symbols and stuff here so. I'm sorry! Hope that helps!!
btw it's a quadratic formula so look up the quadratic formula and just fill that out then simplify to find your answer!! ^^
since you want the height horizontally from the starting height, and that height was 5.4 metres,
-.06x^2 + 9.6x + 5.4 = 5.4
the 5.4 drops out, so
x(-.06x + 9.6) = 0
x = 0 , the starting time
x = 9.6/.06 = 160
it will land after 160 m