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tchrwill
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tchrwill
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A movie theater manager wants to know how many adults and how many children pay admission to a particular movie. The theater charges $10.00 for adult tickets and $5.00 for child tickets. At a showing where 210 tickets were sold the theater collected
The equations of accelerated motion, derived elsewhere, also apply to falling (or rising) bodies with the exception that the term "a" for acceleration is replaced by the term "g” for the acceleration due to gravity). This results in ....Vf = Vo + gt (the
The area of a spherical triangle bounded by arcs of three great circles is defined by A = Pi(r^2)E/180 where r = the spherical radius and E = the spherical excess, defined by E = (A+B+C)-180, A, B and C being the three spherical angles of the sphere.
The velocity required to maintain a circular orbit around the Earth may be computed from the following: Vc = sqrt(µ/r) where Vc is the circular orbital velocity in feet per second, µ (pronounced meuw as opposed to meow) is the gravitational constant of
Using the radius of the Earth and Moon as 3963 miles and 1080 miles, respectively, and the distance between them as 239,000 miles, the surface to surface distance becomes 233,960 miles. From Vf^2 = Vo^2 - 2gs, 0 = Vo^2 - 2(32.2)233,960 or Vo = 282,053 fps
The velocity required to maintain a circular orbit around the Earth may be computed from the following: Vc = sqrt(µ/r) where Vc is the circular orbital velocity in feet per second, µ (pronounced meuw as opposed to meow) is the gravitational constant of
Contrary to popular belief, a spacecraft does not have to reach full escape velocity in order to reach the Moon. The full escape velocity from a 200 mile high circular orbit is 24,400 mph. Assuming the trip starts from a 200 mile high circular orbit, the
There is a clear distinction between a geosynchronous orbit and a geostationary orbit. The early recognition of a geostationary orbit was made by the Russian Konstantin Tsiolkovsky early this century. Others referred to the unique orbit in writings about
The formula that will clear up your problem is ......Vc = sqrt(µ/r) where Vc = the velocity required to keep a body in a circular orbit, in feet/sec., r = the orbital radius in feet and µ = the Earth's gravitational constant or 1.407974x10^16 ft^3/sec^2.
2X + (X - 4) = 32 - X
Can you explain wheightlessness. Do you actually weigh nothing in space or just a percentage of your Earth weight? How much would a 100 lb person weigh on each of the other planets? >> An astronaut, circling the earth in the Space Shuttle, senses that his
There is a clear distinction between a geosynchronous orbit and a geostationary orbit. The early recognition of a geostationary orbit was made by the Russian Konstantin Tsiolkovsky early this century. Others referred to the unique orbit in writings about
* The altitude to the hypotenuse of a right triangle creates two similar triangles, each similar to the original right triangle and to each other. * The altitude to the hypotenuse of a right triangle is the geometric mean between the segments of the
Since the velocity of the train is constant at 54kmph, the average velocity is 54kmph. Proof: D1 = 54(.5) = 27km. D1 = 54(.6666666) = 36 Vav = (27 + 36)/1.16666 = 54kmph.
Time out = 6/2.5 = 2.4 hours Time back = 6/4 = 1.5 hours Average speed for the round trip = (6 + 6/(2.4 + 1.5) = 3.077 kmph
Clearly, I did not understand you. But after reviewing the scenario, the answer is clearly d = sqrt(17000^2 + 4000^2)-4000 = 13,464
The numbers 4; 6; 13; 27; 50; 84 do not form an arithmetic progression as the differences between succsessive terms are not constant. If you take the successive differences of the terms given, n.......1....2....3....4....5....6...
If I understand you correctly the distance you seek is d = sqrt(17000^2 - 4000^2) - 4000
Given the three sides (the largest must be less than the sum of the other two) Find any angle from cosA = (b^2 + c^2 - a^2)/2bc. The remaining angles can be derived from the Law of Sines. Alternatively, find any angle, A for instance, using tan(A/2) = r/(s
Moment of inertia M(i) = 2WR^2/5 about any axis.
Thye following is more than you asked for but I hope you find it interesting. I think you would be surprised to know just how many people have no idea that the Earth moves at all, thinking that the Sun revolves around the Earth. The motion of our Earth
3.14(11^2)/6 - 2(11)5.5/2 = 63.355 - 60.5 = 2.855 sqcm Therefore, D.
Let A = the number of adult tickets C = the number of children tickets Then, A + C = 210 and 10A + 5C = 1355 Can you take it from here?
Part of my previous reply was lost in the posting process. The orbital radius is 3960 + 2.1(104) = 4178.4 miles or 22,061,952 feet. The alleged time to complete one orbit is 10.5(24)3600 = 907,200 seconds making the derived orbital velocity Vc = 152.7fps.
/r] sqrt(sqrt[(1.407974x10^16)/(3960+218.4)5280] = 25,262 feet per second. The orbital period is T = 2(3.14)sqrt[22,061,952^3/1.407974x10^16] = 5487 seconds or 91.45 minutes.
Continuous Compound Interest Formula where FV = Pe^(rt) P = principal amount (initial investment) r = annual interest rate (as a decimal) t = number of interest bearing years FV = amount after time t 110,682 = 45,000e^(30r) from which r = .03 or an annual
As we normally think of it, the static value of gravity on, or above the surface of a spherical body is directly proportional to the mass of the body and inversely proportional to the square of the distance from the center of the body and is defined by the
An asteriod is found a distance from the sun equal to 32 units times the earth's distance. What will be the length of time in years required for this asteroid to make one revolution around the sun? Rast = 32 x 92,960,242 = 2,974,727,744 miles GMsun =
The acceleration due to gravity derives from g = µ/R^2 where G = the acceleration due to gravity µ = the earths gravitational constant = GM G = the universal gravitational constant = 6.67259x10^-11 M = the mass of the earth = 5.97424x10^24 R = the mean
When orbiting at 5.8km/s: From Vc = sqrt(µ/r) where Vc = the velocity of an orbiting body, µ = the gravitational constant of the earth and r the radius of the circular orbit,with µ = GM, G = the universal gravitational constant and M = the mass of the
When orbiting at 6.3km/s: From Vc = sqrt(µ/r) where Vc = the velocity of an orbiting body, µ = the gravitational constant of the earth and r the radius of the circular orbit,with µ = GM, G = the universal gravitational constant and M = the mass of the
g = µ/r^2 gravity on the surface of Mars µ = the gravitational constant of Mars = GM where G = the universal gravitational constant and M = the planet mass r = the radius of Mars = .53(6378)1000 = 3,380,340m G = 6.67259x10^-11 M = .11(5.97424x10^24) =
Considering all rectangles with a given perimeter, one side being provided by a straight given boundry, which one encloses the largest area? Letting P equal the given perimeter and "x" the short side of the rectangle, we can write for the area A = x(P -
What is the monthly deposit required to accumulate to a fund of $1,000,000 over a period of 40 years with deposits starting at the end of the first month and bearing an interest rate of 8% compounded monthly? S(n) = $1,000,000] i = .08/12 = .00666... n =
For Vex = velocity of the exhaust gases g = acceleration due to gravity w = the flow rate of the exhaust gases F = the thrust exerted on the rocket Vex/g = F/w or F = wVex/g
x(x + 1) = x + (x + 1) + 11 Your move.
37 + 10A + B = 59 10A + B = 22 10A + 2 = 22 10A = 20 making A = 2 or 37 + 22 = 59
A convex polyhedron is defined as a solid with flat faces and straight edges so configured as to have every edge joining two vertices and being common to two faces. There are many convex polyhedra, only five of which are considered regular polyhedra.
The following might be of some help to you. 1/23/02 What is the final burnout velocity of the Space Shuttle? The final burnout velocity of the Space Shuttle, or any rocket for that matter, is a function of the altitude at burnout and the orbit that the
Assuming you are seeking the altitude where gravity = g = 6.5m/s^2: As we normally think of it, the static value of gravity on, or above the surface of a spherical body is directly proportional to the mass of the body and inversely proportional to the
Lets look at a typical problem with real numbers. If there are 15 people in a room and each person shakes hands with every other person in the room only once, how many handshakes will take place? There are two ways of looking at this type of problem. The
Vc = sqrt(µ/r) V(A)^2 = µ/r(A) V(B)^2 = µ/r(B) = µ/2r(A) V(B)^2/(2/V(A)^2 = [µ/2r(A)]/[µr(A)] .................= 2 V(B)/V(A) = sqrt2
x + y = 172 110x + 235y = 29,420. Can you take it from here?
From Vc = sqrt(µ/r) where Vc = the velocity of an orbiting body, µ = the gravitational constant of the earth and r the radius of the circular orbit,with µ = GM, G = the universal gravitational constant and M = the mass of the central body, the earth in
Considering all rectangles with the same perimeter, the square encloses the greatest area. Proof: Consider a square of dimensions x by x, the area of which is x^2. Adjusting the dimensions by adding a to one side and subtracting a from the other side
The velocity required to maintain a circular orbit around the Earth may be computed from the following: Vc = sqrt(µ/r) where Vc is the circular orbital velocity in feet per second, µ (pronounced meuw as opposed to meow) is the gravitational constant of
The present value of an ordinary annuity is the sum of the present values of the future periodic payments at the point in time one period before the first payment. What is the amount that must be paid (Present Value) for an annuity with a periodic payment
The formula for calculating a monthly loan payment is R = Pi/[1 - 1/(1+i)^n] where R = the periodic payment, P = the principal, or debt to be paid off, n = the number of payment periods over which the payments will take place, and i = the periodic interest
Letting x, y, and z equal the numbers of .02, .08 and .14 cent stamps. 1-x = 2y + 5 2-z = 3y 3-.02x + .o8y + .14z = 2.26 4-Times 100 yields 2x + 8y + 14z = 226 5-Substituting (1) and (2) into (4) yields ..2(y + 5) + 8y + 14(3y) 6-Can you take it from here?
The Law of Universal Gravitation states that each particle of matter attracts every other particle of matter with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
