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charrice
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charrice
Answers (7)
initial velocity = 42.4 m/s final velocity = 25.0 m/s time = 4.00s a = (final velocity - initial velocity)/time (25.0m/s - 42.4m/s)/ 4.00 s 'sign' of answer determines direction of acceleration
initial velocity = 0 m/s final velocity = 4.92 m/s constant acceleration so, (a) average velocity = (initial velocity + final velocity)/2 (b) distance = average velocity x time substitute and calculate
use the work-energy theorem determine mass = 16.0N/9.8 m/s^2 initial velocity = 0; so initial KE = 0 final velocity = 15.0 m/s final height = 0; so final PE = 0 initial height = 150 sin 28.0 degrees substitute values in the work-energy theorem expression
initial velocity = 78.3 m/s final velocity = 0 m/s distance traveled - 959 m a = ? use (final velocity)^2 = (initial velocity)^2 + 2ad solve equation for 'a'.
power = force x velociy. Plug the values in and you have your answer.
Ft = m(final velocity) - m(initial velocity) F = ma so equation changes to mat = m(final velocity) - m(initial velocity) plug in values and solve for 'a'
Add all the Ps 4p-13p-p = -10p divide both sides by -10 to isolate P -10P = -150 -10p/-10p = -150/-10 p = 15 check by inserting calculated value into original equation
