To find the magnitude and direction of the jet's acceleration, we can use the equation of motion:
v^2 = u^2 + 2as
where:
v = final velocity (0 m/s since the jet comes to rest)
u = initial velocity (78.3 m/s)
a = acceleration (unknown)
s = distance traveled (959 m)
Rearranging the equation to solve for acceleration (a), we have:
a = (v^2 - u^2) / (2s)
Substituting the given values into the equation:
a = (0 - (78.3)^2) / (2 * 959)
a = (-6112.89) / (1918)
a ≈ -3.19 m/s^2
The negative sign indicates that the acceleration is in the opposite direction of the initial velocity (i.e., north).
Therefore, the magnitude of the jet's acceleration is approximately 3.19 m/s^2, and its direction is north.